Recent content by Lynne
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Seagate ST3750640AS 750GB: Maximum Data Flow and Outer Zone Sectors Calculation
I'm very sorry for mistyping here, it is actually 15 000. 15 000:60=250 Thanks for helping me out!- Lynne
- Post #10
- Forum: Engineering and Comp Sci Homework Help
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Seagate ST3750640AS 750GB: Maximum Data Flow and Outer Zone Sectors Calculation
@ Redargon I think your answers are more correct than my and both are valid (in my case). My problem is I just don't understand how to calculate data flow from disk (media transfer rate) or how to determine number of sectors in disk, ect. Coud it be fomula:w=\frac{n*512}{t} where n -...- Lynne
- Post #6
- Forum: Engineering and Comp Sci Homework Help
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Seagate ST3750640AS 750GB: Maximum Data Flow and Outer Zone Sectors Calculation
Thank you for reply! So 1 sector= 512 bytes 624:4160=0.15 Mbit - can read in one rotation 0.15:8*1000=18.75KB 18.75:0.512=36.61 - sectors in outer track- Lynne
- Post #3
- Forum: Engineering and Comp Sci Homework Help
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Seagate ST3750640AS 750GB: Maximum Data Flow and Outer Zone Sectors Calculation
Hi, This is probably a simple question, but not for me. Seagate ST3750640AS 750GB can provide maximum data flow from disk 624 Mbit/s. How many sectors are in outer zone tracks if average rotation latency is 4.16ms? I've no idea how to calculete this- Lynne
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- Disk
- Replies: 9
- Forum: Engineering and Comp Sci Homework Help
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Critical Points of f(x)=\frac{\sqrt[3]{x-4}}{x-1} - Max/Min Value
Homework Statement Determine function f(x)=\frac{\sqrt[3]{x-4}}{x-1} critical points and find max and min value in given interval [2; 12] The Attempt at a Solution 1) I've to find derivative: f(x)'=\frac{(\sqrt[3]{x-4})' (x-1)-(\sqrt[3]{x-4})(x-1)'}{(x-1)^2}=...- Lynne
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- Critical points Points
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Derivative of Trigonometric Expression: y' = -cos2x | Derivative Help #2
Yes, it's my mistake. Denominator of the second term is tangent.- Lynne
- Post #5
- Forum: Calculus and Beyond Homework Help
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Derivative of Trigonometric Expression: y' = -cos2x | Derivative Help #2
Homework Statement y= \frac{sin^2 x}{1+ ctgx} +\frac{cos^2 x}{1+ ctgx} Find: y' The Attempt at a Solution Answer is-cos2x but again I can't find it. Where am I making a mistake? y'=(\ \frac{sin^2 x}{1+ ctgx} +\frac{cos^2 x}{1+ ctgx} \ )'= \frac{(sin^2 x)'(1+ ctgx) -( sin^2...- Lynne
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- Derivative
- Replies: 5
- Forum: Calculus and Beyond Homework Help
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How do I find the derivative of ln with fractions and trig functions?
Thank you very, very much!- Lynne
- Post #5
- Forum: Calculus and Beyond Homework Help
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How do I find the derivative of ln with fractions and trig functions?
Hi, I need help on this: Homework Statement y = ln \frac{\sqrt{3}-\sqrt{2} cos x}{\sqrt{3} +\sqrt{2} cos x} find y' The Attempt at a Solution I know that answer should be: \frac{2\sqrt6 \ sinx}{3-2cos^2 x} , but can't find it: y'= ( ln \frac{\sqrt{3}-\sqrt{2} cos...- Lynne
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- Derivative
- Replies: 4
- Forum: Calculus and Beyond Homework Help
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Composition of Functions (check me)
Hi, Homework Statement Given: f(x)=x^2+2 and g (x)=\sqrt{x} Find: f \circ g and g \circ f 2. The attempt at a solution f \circ g =f(g(x))=x+2 , where x\in (-\infty ; +\infty) g \circ f =g(f(x))=\sqrt{x^2+2} where x\in (-\infty ;+ \infty) I haven't done this for a...- Lynne
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- Composition Functions
- Replies: 1
- Forum: Precalculus Mathematics Homework Help
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Are These Vectors Linearly Independent?
Thank you very much.- Lynne
- Post #6
- Forum: Precalculus Mathematics Homework Help
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Are These Vectors Linearly Independent?
Homework Statement Given vectors: a1 = (1; 2; 0), a2 = (2; 1; 3), a3 = (0; 3; -3). Find out if these vectors are linearly independent. Homework Equations The Attempt at a Solution \begin{cases}...- Lynne
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- Independent Linearly Vectors
- Replies: 5
- Forum: Precalculus Mathematics Homework Help