1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Composition of Functions (check me)

  1. Mar 16, 2009 #1

    1. The problem statement, all variables and given/known data
    Given:[tex] f(x)=x^2+2[/tex] and [tex] g (x)=\sqrt{x}[/tex]

    Find: [tex] f \circ g [/tex] and [tex] g \circ f [/tex]

    2. The attempt at a solution
    [tex] f \circ g =f(g(x))=x+2 [/tex], where [tex] x\in (-\infty ; +\infty) [/tex]

    [tex] g \circ f =g(f(x))=\sqrt{x^2+2} [/tex] where [tex] x\in (-\infty ;+ \infty) [/tex]

    I haven't done this for a while, and I'm not sure about my solution. Is it correct?
  2. jcsd
  3. Mar 16, 2009 #2


    User Avatar
    Science Advisor
    Homework Helper

    Almost. Except g(x) is only defined for x in [0,infinity).
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Composition of Functions (check me)
  1. Composite functions (Replies: 4)

  2. Composite functions (Replies: 4)

  3. Composite functions (Replies: 3)

  4. Composite functions (Replies: 21)

  5. Composition functions (Replies: 14)