# Recent content by m_s_a

1. ### Complex numbers

whith out finding all roots' http://img155.imageshack.us/img155/1870/dddgh6.th.png [Broken]
2. ### Question from test capabilities

Homework Statement from test capabilities I want to know the right answer please True Or False Questions stereographic projection for space R3 is the set of points (x, y, 0) and radius 1 is the circle X2 + Y2 = 1 stereographic projection for space R3 is the set of points (x, y...
3. ### Limit of a sine

Unfortunately, I have erred in solution Equal second incorrect
4. ### Need Integral Help!

http://www.4nw.net/s_thumbnailer-6-2008/hb6z6g1g.JPG [Broken]
5. ### Integrate from 0 to b

http://www.4nw.net/get-6-2008-6x9cp3w5.JPG[/URL] [Broken] cont. http://www.4nw.net/get-6-2008-syhlk7fm.JPG[/URL] [Broken]
6. ### A function

Try Term is not defined Time is Open:devil:
7. ### A function

an=/=0 Because Rotation does not appear in a double -
8. ### A function

Challenge write Polynomail More than double the rotation an=/=0 r=0 or A negative number
9. ### A function

Yes .. Yes This is what I want to say
10. ### A function

Reference in rotation among the transactions +,-,+,-,+ if f(r) =0 then r>0 r=root in f
11. ### Understanding epsilon-delta def of limits

http://www.up07.com/up7/uploads/df5040ccd8.jpg http://www.up07.com/up7/uploads/4c7f5603e7.jpg No requirement that the value of f(x0) The smaller values for delta & epsilon Leads to ........what?
12. ### Understanding epsilon-delta def of limits

Perhaps in this way can Be clear idea http://www.up07.com/up7/uploads/6225e0aea0.jpg
13. ### 2 Mini Q.

Hi king:smile: O.K. used (I) for Contour = sum of Curves , and Closed and used (II) for any Curve Q.2 Now z1(t)=t , 0=<t=<5 z2(t)=5+it , 0=<t=<5 z3(t)= t+5i , 5=<t=<0 z4(t)=it , 5=<t=<0 :yuck:
14. ### 2 Mini Q.

Dear Dick مرحبا سعيد يرؤيتك 1) I can not find an answer in books,In books sometimes use pattern,Sometimes using type IIusing In your answer: They both indicate integral over the contour Do you clarify if possible 2) C1:z(t)=t , 0=<t=<5 C2:z(t)=5-t+5i , 0=<t=<5 C3:z(t)=5-t+5i ...