Is paramitric Equation Correct?

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SUMMARY

The discussion focuses on the correctness of parametric equations used to describe contours in complex analysis. The user presented several parametric equations for contours C1, C2, C3, and C4, but there were notable errors, including duplicate labels and incorrect ranges. The main conclusion is that if the contours are meant to be the same, the equations should reflect that consistency, particularly in the notation of closed versus open contours.

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Homework Statement



http://up5.m5zn.com/photos/00017/t4x1262r70cu.jpg[/URL]
http://up5.m5zn.com/photos/00017/rpbn4bsfcace.jpg[/URL]

Homework Equations





The Attempt at a Solution


C1:z(t)=t , 0<t<5
C1:z(t)=5+it , 0<t<5
C2:z(t)=1-t+5i , 0<t<5
C3:z(t)=5-t+5i , 0<t<5
C4:z(t)=i(1-t) , 0<t<5
Is paramitric Equation Correct?
 
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1) Not really any difference as far as I know. They both indicate integral over the contour C. 2) The parametric form for the contour has several mistakes. Can you find one? I'll get you started. The contour has 4 segments, you've listed 5. Two of them labelled C1. What's up with that?
 
Dear
Dick
مرحبا
سعيد يرؤيتك
1)
I can not find an answer in books,In books sometimes use pattern,Sometimes using type IIusing
In your answer:
They both indicate integral over the contour
Do you clarify if possible
2)

C1:z(t)=t , 0=<t=<5
C2:z(t)=5-t+5i , 0=<t=<5
C3:z(t)=5-t+5i , 0=<t=<5
C4:z(t)=i(5-t) , 0=<t=<5
Sorry for error
I will try again.
Thanks
See you
 
For (1), IF "C" represents the same contour in both integrals, then, as Dick said, they are the same. However, I suspect that the question did not mean to imply that. If the two different "C"s may mean different contours, then the first form implies that C is a closed contour while the second does not.


For (2), now you've got C2 and C3 exactly the same! (Your second "C1" in your first answer should have been "C2".)
 
Hi king:smile:
O.K.
used (I) for Contour = sum of Curves , and Closed
and used (II) for any Curve

Q.2
Now
z1(t)=t , 0=<t=<5
z2(t)=5+it , 0=<t=<5
z3(t)= t+5i , 5=<t=<0
z4(t)=it , 5=<t=<0


 

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