Recent content by man_in_motion

how would using the parallel axis theorem help? I don't know what u mean about the google search.

Homework Statement There are 2 models of rugbeaters. Model A has a 1m long handle and a 40cm edge length square. The handles mass is 1kg and the squares mass is 0.5kg. Model B has a 0.75m long handle and a square that has 30cm edge length. The mass of the handle is 1.5kg and the mass of the...

got it now...I miss understood the question and thought that there was no acceleration:rolleyes: so let me get this straight: whenever something is rotating there's going to be angular acceleration right? so that means I will NEVER use a formula like x=wt where w is the angular velocity and x...

In an example question the revolutions per minute where 500rev/min. The question asked how many revolutions the disk makes in 5.5s. The solution started with the formula w=w_o+\alpha t I'm wondering why one can't just convert rev/min into raidans/sec and multiply that number by 5.5s? kind of...

Homework Statement Walking by a pond, you find a rope attached to a tree limb 5.2 m off the ground. You decide to use the rope to swing out over the pond. The rope is a bit frayed but supports your weight. You estimate that the rope might break if the tension is 80 N greater than your...

Energy is conserved K_f+U_f=K_o+U_o K_0 goes to 0 and rewriting the equation we get K_f=U_o-U_f=\Delta U Initially there is only potential energy due to gravity, when the block is in the air U_o_g=mgy=2.4kg(9.81m/s^2)5m There are 2 final potential energies: one for the gravity and...

thanks tiny-tim, though I'm still not entirley convinced. consider: K_f-K_o = K_f = U_f-U_o=U_f_g+U_f_s-U_g_o=(mg(0.25m)+\frac{1}{2} \cdot \frac{mg}{0.25m}0.15^2m)-mg(5m)=\frac{1}{2}mv^2 Then I solve for v and I get v=\sqrt{\frac{2(mg(0.25)+\frac{1}{2} \cdot \frac{mg}{0.25} \cdot 0.15 -...

Homework Statement A 2.4kg block is dropped onto a spring from hieght of 5m. When the block is momentarily at rest, the spring is compressed 25cm. Find the speed of the block when the compression of the spring is 15cm. answer: 10m/s Homework Equations K=\frac{1}{2}mv^2 U_g=mgh...

Homework Statement The apparatus (see link to image) is used to measure the free fall acceleration g by measuring the acceleration of the two blocks connected by a string over a pulley. Asume a massless, frictionless pulley and a massless string...

[img=http://img44.imageshack.us/img44/4338/questionw.th.png] [img=http://img44.imageshack.us/img44/4338/questionw.th.png] stupid too short message

Homework Statement There is a box on a platform with mass 3.5kg and it has two ropes connected to it. On the end of each of these ropes are 2 other boxes hanging off the table (so only F_y component). One box is 2.5kg and the other is 1.5kg. I need to find the acceleration of all the boxes...