2 weights on a pully, show formula

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SUMMARY

The discussion focuses on calculating the acceleration of two blocks connected by a string over a massless, frictionless pulley, using Newton's laws. The derived formula for acceleration is a = (m1 - m2) / (m1 + m2), where m1 and m2 represent the masses of the blocks. The analysis includes drawing free body diagrams and evaluating the behavior of the system under different mass conditions, specifically when m1 equals m2, and in the limits of m1 much greater than m2 and m1 much less than m2.

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  • Understanding of Newton's laws of motion
  • Ability to draw and interpret free body diagrams
  • Basic knowledge of kinematics and dynamics
  • Familiarity with mass and gravitational force equations
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Homework Statement



The apparatus (see link to image) is used to measure the free fall acceleration g by measuring the acceleration of the two blocks connected by a string over a pulley. Asume a massless, frictionless pulley and a massless string.
http://img3.imageshack.us/img3/3459/phys.th.png
a) draw a free body diagram of each block
http://img16.imageshack.us/img16/3523/diagrams.th.png
b)use the free body diagrams and Newton's laws to show that the magnitude of acceleration of either block and tension in string are a=(m1-2)/(m1+2)
c)do these expressions give reasonable results if m1=m2 in the limit that m1 >> m2 and in the limit that m1 << m2 ? Explain

Homework Equations



Fnet=ma
Fg=mg

The Attempt at a Solution


F=ma
T_1=-T_2
T_2=(m_2)g
T_1=(m_1)g
=>m_1(g)=-m_2(g)
 
Last edited by a moderator:
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Assume block one moves downwards, so the resultant force on m1 is

m1a=mg-T

So what is the resultant force on m2?

Now you have two equations in T and a, you can now eliminate T.
 

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