Recent content by Maxo

Thank you, I would pretty much call this a perfect answer. :)

Here's another related question, about if it's possible to write using Sigma notation. It's about this general formula for an arithmetic sum: Is there any way to write this general sum using the sigma notation? If so, how could it be written with Sigma notation?

Where? Actually I shouldn't have written that equation. I want to know how to do it, without using this equation. The point of the exercise is actually to make an example which leads to this equation. Is this possible?

Homework Statement Show that ^{2}log(e)=\frac{1}{ln2} Homework Equations ^{a}log(x) = ^{a}log(b)\cdot ^{b}log(x)^{a}log(x)=\frac{^{b}log(x)}{^{b}log(a)} The Attempt at a Solution How can this be shown? I assume it can be done just using logarithm laws, but I don't see how. I tried manipulating...

Well for example here: http://www.wolframalpha.com/input/?i=arg%28%E2%88%921%E2%88%92sqrt%283%29i%29%3D4pi%2F3 it says false.

Homework Statement Calculate argument of complex number -1-\sqrt{3}i Homework Equations The Attempt at a Solution The argument of this is -120 degrees but why couldn't we as well say it's 240 degrees? Since going 240 degrees will go to the same point as -120 degrees. Why is this false?

Now I see it :) Is there some rule (algorithm) / procedure to follow when factoring like this?

I made a misstake, it should be a(c+di)-b(d-ci). Anyway so you're saying (c+di) and (d-ci) can be made the same. I actually don't see how that could be done? I mean both the real and the imaginary parts of these expressions are different. How are they the same?

Homework Statement Factor the expression ac-bd+adi+bci Homework Equations The Attempt at a Solution We can factor the variable 'a' which gives: a(c+di)-bd+bci The common factor in the remaining terms is b, and if we also factor out b we get a(c+di)-b(d+ci) But this is not the...

Thank you, you explain very well! I understand everything better now. So if we write this again the opposite direction and then add column wise, we get that each term is equal to 2a+(n-1)d and we have n such terms, so 2S = n(2a+(n-1)d) = 2an + nd(n-1), so S = an + nd(n-1)/2. In other words...

Allright, so we have \sum ^{n}_{k=1}(2k-1)=\sum ^{n}_{1}2k-\sum ^{n}_{1}1 The second term is easy since we see that we have 1 n times so 1*n = n as you already wrote. Can it be also calculated using the general equation? When I try I get (1(1+1))/2=2/2=1 which is not correct. Also if we just...

Homework Statement By using the general equation for an arithmetic series, find a formula for calculating the series 1+3+5+...+(2n-1) Homework Equations General equation for an arithmetic series: \sum ^{n}_{k=1}k=\frac{n(n+1)}{2} The Attempt at a Solution Using the general equation we have...

Since you were rude already from the beginning, the quickest way possible, according to your own theory you are the one who must have very serious problems, so why don't you follow your own advice and take those elsewhere? I already told you you are not helpful at all, unlike very many other...

There are very many helpful people on these forums but you are definitely not one of them. Please do as all a favor and refrain from posting, at least in my threads, and let the better people post instead. So the questions (only directed towards good people) are still the following: What...

sophiecentaur: I guess you didn't read UltrafastPEDs post (although it's quite obvious, maybe you don't know that you are supposed to read previous posts before writing), where he said that the ideal gas law doesn't apply here, to which I already answered. So these questions still remain: Ok...