Can different arguments be correct for the same complex number?

AI Thread Summary
The argument of the complex number -1 - √3i is -120 degrees, but it can also be represented as 240 degrees since both angles point to the same location on the complex plane. However, textbooks often adhere to conventions that restrict the principal argument to a specific range, such as (-180, 180] or (0, 360) degrees, to avoid ambiguity. The principal argument is typically the smallest angle, which is why -120 degrees is preferred in this case. Tools like Wolfram Alpha follow the principal argument convention, which can lead to confusion if users are unaware of these rules. Understanding these conventions is essential when interpreting results from calculators or software.
Maxo
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Homework Statement


Calculate argument of complex number
-1-\sqrt{3}i

Homework Equations



The Attempt at a Solution


The argument of this is -120 degrees but why couldn't we as well say it's 240 degrees? Since going 240 degrees will go to the same point as -120 degrees. Why is this false?
 
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Why do you say it is false? Yes, -120 degrees is the same as 360- 120= 240. If your textbook gives -120 as the argument that does not necessarily mean 240 is not. But perhaps your text is using a particular convention here: in order to avoid ambiguity some texts require that angles be given between -180 and 180 degrees, others between 0 and 360 degrees.

(Personally, I would have said that the argument was 4\pi/3. I am a little surprised you are using degrees rather than radians.)
 
The answer can be any multiple of 2\pi radians, but it's just been chosen so that the principal argument (smallest angle) is in the range (-\pi,\pi]. It's just a custom really.
 
Maxo said:

Wolfram Alpha is abiding by the principal argument custom. When you use calculators, you sometimes need to have an understanding of what their unexpected results could mean.

Like this one:

http://www.wolframalpha.com/input/?i=%28-1%29%5E%281%2F3%29

Notice it says "Assuming the principal root". There are 3 roots, and the one with the smallest argument which is was returned to the user, while many people would expect the answer to be -1.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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