Recent content by maysenator

OK shot in the dark here but here is my question prefaced with a small back-story. Im a undergrad in mechanical engineering program. I am currently having a bit of trouble in Dynamics class. A lot of people who are much smarter than me say its nothing more than applied physics. Like some guys...

can someone just point me in the direction of finding the unit tangent vector in the direction of motion please? i don't need a entire solution

Homework Statement Suppose that the Celsius temperature at the point (x, y) in the xy plane is T(x,y) = xsin(2y) and that the distance in the xy plane is measured in meters. A particle moving clockwise around the circle of radius 1m centered at the origin at the constant rate of 2 m/s a...

i wouldn't mind some insight on this as well.

i figured it out, only a small mistake for anyone who may encounter this exact scenario i was forgetting dt/ds as 1/lvl where as ds/dt is mag v small dumb error

"box of primes" over l V X a l ^2 Homework Statement Find B, and t for these space curves (t = torsion) r(t) = (3sint)i + (3cost)j + 4tk Homework Equations Ok, so in my textbook i have two different equations to find the answer to this. the "box of primes" over l V X a l ^2...

just wanted to pop back in here and say thanks for the help, was just getting frustrated. ended up getting a decent grade in the class thanks to your help and others from this site. never taking a calc based phys course during the summer again. I need more time to learn LOL

great i can't drop this class because then ill lose my financial aid. time to commit suicide

thanks for your help man, I am giving up.. dropping the class going to try again next semester paace

i don't understand what you mean. the block is moving up the slope at .64 ms its Fg is 9.8 * 2.1 right? so i have a, and fg right there. the normal force is the force the slope is pushing back up into the mass right? moving in the x direction is Fg * cos 60 right? or Fg sin 60...

i didnt use f = ma for the left one. I thought that 20.58N * sin60 would give the force parallel to the slope getting 17.83 and then 20.58 cos 60 = 10 . 29 N would the the normal force so what... then i have ... Fnet = ma~ t1 + 20.58 + 10.29 = (2.1)(.64) (all the forces?) is that right...

I don't get what I am missing i have done everything you have said ( i think ) but on my paper i don't have enough information to do anything with?

but but but i can't find the tension with this information>? i need to use information from the other diagram right??

are you saying it SHOULD be for one mass only or that was my mistake?? sorry again, thank you so much i feel closer already. this is what i have drawn out so far

1.34/.64 = 2.09 f = ma?