Trouble Graphing Multivariable Functions

_Steve_
Messages
19
Reaction score
0
So the function I'm working with is:

f(x,y) = 1/sqrt(1-x^2-4y^2)

First, they want me to find the Domain and Range, which I found to be:
D: x^2 + 4y^2 < 1
R: (0,1]
Then they want me to sketch level curves and cross sections, then sketch f(x,y)
I'm having trouble with the sketching, I understand the concept of level curves, but when I make f(x,y) = k I'm not quite sure where to go from here... Does anyone have any graphing tips that I could use? Thanks!
 
Physics news on Phys.org
i wouldn't mind some insight on this as well.
 
You know that 0 ≤ x2 + 4y2 because x2 & y2 are each non-negative.

∴ 0 ≤ x2 + 4y2 > 1

So to find level curves, you must choose k so that 0 ≤ 1/k ≤ 1 .
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top