Recent content by menco

They are parts b,c,d when they want the friction factor, pump power and distance from reservoir to avoid cavitation. I can't seem to solve the NPSM but will keep trying.

Thanks that helped get it sorted, changed my P_2 value and found the right answer

Homework Statement The pump in the system below has an efficiency of 75%. The atmospheric pressure is 101 kPa and the vapor pressure is 2.3 kPa (in absolute units). Assume kinematic viscosity is 0.96x10-6 m2/s. Neglect minor losses. a) Calculate the velocity through the main pipe and of...

Homework Statement Solve the following system of partial differential equations for u(x,y) Homework Equations du/dy = 2xyu du/dx = (y^2 + 5)u The Attempt at a Solution I am honestly not sure where to start, my lectures and tutorials this week have not been helpful at all. My guess is to...

Thanks a lot for your help!

I think I see now so Q=Q_max exp^-t/RC Q_max = (500x10^-12)(30x10^3) = 15x10^-6 Q = (500x10^-12)(14142.5) = 7x10^-6 t=(-12.5) ln ((7x10-6)/(15x10^-6)) = 9.5s

I think I see now so Q=Q_max exp^-t/RC Q_max = (500x10^-12)(30x10^3) = 15x10^-6 Q = (500x10^-12)(14142.5) = 7x10^-6 t=(-12.5) ln ((7x10-6)/(15x10^-6)) = 9.5s

Yeah I wasnt sure if I should factor in the 4 tyres as I wasn't sure if maybe it just takes the path of least resistance through one tyre. Every time i calculate I get a negative value for time, I know it's not suppose to be so that's why I am lost 100/4 = 25Gohm So T=RC =(25x10^9)(500x10^-12)...

Homework Statement When the cehicl stop's in the team's pit stop, consider the time as being t=0. If the potential difference between the car and ground is 30kV, the car-ground capacitance is 500pF and the resistance of each tyre is 100Gohm, determine the time it takes for the car to discharge...

Ah yes i see I forgot all about +C, which is the constant of integration. So if I use 100/3 = 256/3 + C, C = (-52) Therefore the final function will be ((4(2x+7)^3/2) / (3)) - 52 then when f(9/2) = 100/3

f(9/2) = 256/3 So it is not the case, I'm a little unsure of what you mean by fix it?

Yes we have just started integrals, by using substitution I found f(x) = (4(2x+7)^3/2) / 3 Does the point (9/2, 100/3) have anything to do with the problem?

the rate of change of the function is 4*sqrt(2x+7)?

To find the slope of a tangent line take the derivative of the function and substitute in the point of contact if known.

I know how to find the slope and equation of a tangent line fairly easy but trying to reverse it is confusing me