Recent content by MysticDude

Ammonium nitrate is a salt. NH4NO3. I can't really answer the last question.

Homework Statement 1) Having nitrogen gas, hydrogen gas, and oxygen gas, obtains ammonium nitrate (write down the equation for each step). Homework Equations Nitrogen gas = N2 Hydrogen gas = H2 Oxygen gas = O2 The Attempt at a Solution So we have 2N2 + 4H2 + 3O2 -> (NH4)2(NO3)2 but...

Well, as many the two users above me already said about the battery being uselessly charged, it's true. I used to have a laptop (well, I got another one :D) and the battery would not last for more than 10 minutes like you said. So what I'm doing with my new one is that whenever I'm running it...

I thought schools used Macs because of school discounts or something. In my high school, the laptops that are given to the teachers are Macs, but they all also have a Windows desktop. Personal preference, games, in my opinion it is easier to use than Macs, and of course...the toolbar!

I know that I should watch significant numbers. I just plugged in everything directly into my calculator. Thanks a bunch for checking!

I changed that a minute after I saw the negative. I guess the picture didn't update o.o Anyway, I got something like 192764220 molecules/milliliter. Can you compare?

Okay, so by using Coto's equation, I get 3.207 x 10-13\frac{mol}{L}. So to get \frac{molecules}{milliliter}, I would have to do this: 3.207 x 10^{-13}\frac{mol}{L} x \frac{1 L}{1000 mL} x 6.022x10^{23}\frac{molecules}{mol}...in order to get my answer, right?

Yes, but I'm missing the volume. I only have the 300 km in the air for information.

Homework Statement At a height of 300km above the Earth's surface, an astronaut finds that the atmospheric pressure is about 10-8 mmHg and the temperature 500 K. How many molecules are there per milliliter at this altitude? Homework Equations The Attempt at a Solution I first...

Okay thanks, you've been a big help! I think I'm going to go without idea since it seems more reasonable. Once again, thanks a lot!

Well, my teacher didn't go into too much detail about these problems. My teacher does put attention to detail sometimes though. So if the skydiver "just jumped" then there would be a the force of the air rushing against him. In other words, should it be something like this: O--------> air force...

Thanks for your help! By the way, were the other ones correct?

So it's just like: |\ ..\ ...\...Tension at 25° ...\ ...O ...| ...|...mg ...| ...V Hopefully you can understand this, if not, I'll upload a picture.

Now that I think more about it, I think that "force of bob" should just be T for tension. I guess that that counteracts mg so there really is no normal in the free body diagram?

Homework Statement Draw free body diagrams: A rectangular block being accelerated on a horizontal, frictionless surface. A skydiver who had just jumped from a plane and hasn't reached terminal velocity. A cube being accelerated up a 30° incline with μk > 0. A pendulum bob that has just been...