Concentration of Molecules in the Air

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Discussion Overview

The discussion revolves around calculating the concentration of molecules in the air at an altitude of 300 km, given specific atmospheric pressure and temperature conditions. Participants explore the application of the Ideal Gas Law and related calculations to determine the number of molecules per milliliter.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant expresses uncertainty about how to proceed with the calculation due to the lack of explicit volume information, initially considering the Ideal Gas Law.
  • Another participant clarifies the relationship between pressure, temperature, and the number of moles per volume, suggesting the use of the Ideal Gas Law to find n/V.
  • A different participant emphasizes that the calculation does not require a specific volume, as the question asks for concentration (n/V) based on given pressure and temperature.
  • One participant calculates a concentration of 3.207 x 10-13 mol/L and outlines the steps to convert this to molecules per milliliter.
  • Another participant corrects a minor error in the Avogadro's number notation and confirms the calculation process, while also providing their own result for comparison.
  • Participants discuss the importance of significant figures in their calculations, acknowledging the need for precision.

Areas of Agreement / Disagreement

Participants generally agree on the approach to calculate the concentration of molecules, although there is some initial confusion regarding the need for volume. The discussion remains focused on refining the calculations and ensuring accuracy.

Contextual Notes

Some participants note the importance of significant figures and the correct application of constants, indicating that precision in calculations is a concern. There is also a mention of a potential misunderstanding regarding the volume aspect of the problem.

Who May Find This Useful

This discussion may be useful for students or individuals interested in gas laws, atmospheric science, or those working on related homework problems in physics or chemistry.

MysticDude
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Homework Statement


At a height of 300km above the Earth's surface, an astronaut finds that the atmospheric pressure is about 10-8 mmHg and the temperature 500 K. How many molecules are there per milliliter at this altitude?


Homework Equations





The Attempt at a Solution


I first thought that I had to calculate the amount of moles in area then multiply that by Avogadro's number. But then I realized that there is no amount of volume given here, only the height, as I was thinking about using the Ideal Gas Law. All I need is the volume, but I don't know how to get it. Was I even on the right track here?
 
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[itex]PV = nRT \implies V/n = RT/P \implies n/V = P/RT[/itex]. To simplify your calculation, take the universal gas constant to be: [itex]R = 0.08206 \frac{\textrm{atm}\cdot\textrm{L}}{\textrm{K}\cdot\textrm{mol}}[/itex].
 
Coto said:
[itex]PV = nRT \implies V/n = RT/P \implies n/V = P/RT[/itex]. To simplify your calculation, take the universal gas constant to be: [itex]R = 0.08206 \frac{\textrm{atm}\cdot\textrm{L}}{\textrm{K}\cdot\textrm{mol}}[/itex].

Yes, but I'm missing the volume. I only have the 300 km in the air for information.
 
They're looking for mols/mL ... so no, you don't need a volume, you need an n/V ... which only requires knowledge of P and T. (Liter is a measure of volume).
 
You are given volume. They ask for number of molecules per milliliter.
 
Okay, so by using Coto's equation, I get 3.207 x 10-13[tex]\frac{mol}{L}[/tex].
So to get [itex]\frac{molecules}{milliliter}[/itex], I would have to do this:
[tex]3.207 x 10^{-13}\frac{mol}{L} x \frac{1 L}{1000 mL} x 6.022x10^{23}\frac{molecules}{mol}[/tex]...in order to get my answer, right?
 
Last edited:
Exactly... except [itex]N_A = 6.022 \cdot 10^{23}\frac{\textrm{moleculues}}{\textrm{mol}}[/itex]. Not -23 :).
 
Coto said:
Exactly... except [itex]N_A = 6.022 \cdot 10^{23}\frac{\textrm{moleculues}}{\textrm{mol}}[/itex]. Not -23 :).

I changed that a minute after I saw the negative. I guess the picture didn't update o.o

Anyway, I got something like 192764220 molecules/milliliter. Can you compare?
 
Close enough to what I get. Watch significant figures.
 
  • #10
Borek said:
Close enough to what I get. Watch significant figures.
I know that I should watch significant numbers. I just plugged in everything directly into my calculator. Thanks a bunch for checking!
 

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