Chemistry Concentration of Molecules in the Air

AI Thread Summary
At an altitude of 300 km, an astronaut measures atmospheric pressure at 10^-8 mmHg and temperature at 500 K. The discussion revolves around calculating the number of molecules per milliliter using the Ideal Gas Law, specifically focusing on the relationship between pressure, temperature, and volume. Participants clarify that the calculation does not require a specific volume, as the desired outcome is the number of molecules per unit volume (n/V). The final calculation yields approximately 192,764,220 molecules per milliliter, emphasizing the importance of significant figures in the result. Overall, the conversation highlights the application of gas laws in determining molecular concentration at high altitudes.
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Homework Statement


At a height of 300km above the Earth's surface, an astronaut finds that the atmospheric pressure is about 10-8 mmHg and the temperature 500 K. How many molecules are there per milliliter at this altitude?


Homework Equations





The Attempt at a Solution


I first thought that I had to calculate the amount of moles in area then multiply that by Avogadro's number. But then I realized that there is no amount of volume given here, only the height, as I was thinking about using the Ideal Gas Law. All I need is the volume, but I don't know how to get it. Was I even on the right track here?
 
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PV = nRT \implies V/n = RT/P \implies n/V = P/RT. To simplify your calculation, take the universal gas constant to be: R = 0.08206 \frac{\textrm{atm}\cdot\textrm{L}}{\textrm{K}\cdot\textrm{mol}}.
 
Coto said:
PV = nRT \implies V/n = RT/P \implies n/V = P/RT. To simplify your calculation, take the universal gas constant to be: R = 0.08206 \frac{\textrm{atm}\cdot\textrm{L}}{\textrm{K}\cdot\textrm{mol}}.

Yes, but I'm missing the volume. I only have the 300 km in the air for information.
 
They're looking for mols/mL ... so no, you don't need a volume, you need an n/V ... which only requires knowledge of P and T. (Liter is a measure of volume).
 
You are given volume. They ask for number of molecules per milliliter.
 
Okay, so by using Coto's equation, I get 3.207 x 10-13\frac{mol}{L}.
So to get \frac{molecules}{milliliter}, I would have to do this:
3.207 x 10^{-13}\frac{mol}{L} x \frac{1 L}{1000 mL} x 6.022x10^{23}\frac{molecules}{mol}...in order to get my answer, right?
 
Last edited:
Exactly... except N_A = 6.022 \cdot 10^{23}\frac{\textrm{moleculues}}{\textrm{mol}}. Not -23 :).
 
Coto said:
Exactly... except N_A = 6.022 \cdot 10^{23}\frac{\textrm{moleculues}}{\textrm{mol}}. Not -23 :).

I changed that a minute after I saw the negative. I guess the picture didn't update o.o

Anyway, I got something like 192764220 molecules/milliliter. Can you compare?
 
Close enough to what I get. Watch significant figures.
 
  • #10
Borek said:
Close enough to what I get. Watch significant figures.
I know that I should watch significant numbers. I just plugged in everything directly into my calculator. Thanks a bunch for checking!
 

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