Recent content by N2O2

You should consider r in the integral as a vector. and since the charge distribution has symmetry with respect to x and y axes, we only consider z component of r which is Rcosθ. You can check x and y and make sure that they are zero.

This is a general statement. Of course we should set a specific arrangement to obtain a result. for example put Qi on ith conductor and assume jth conductor to be grounded and Q on other conductors to be zero. But I haven't found the correct conditions.

Homework Statement I want to prove that coefficients of potential are non-negative. i.e. Pij ≥ 0 Homework Equations By coefficients of potential method we know that in a system of conductors the potential on ith conductor is related to charges on conductors by: \Phii = \sum Pij Qj...

I think you need to use P=σAT4, it gives you the energy flow from a surface with temperature T. σ is Stefan–Boltzmann constant and is equal to 5.67x10-8 J/sm2K4

The best way is to find the equivalent circuit and then use \frac{1}{2}CV2

Pay attention that the angle between two vectors won't be negative ... There should be an angle that its cos is - and its sin is + angle: 180 - 66 = 114 degree