Recent content by onemic

doing it that way I get: ##a^2-4a=0## ##a(a-4)=0## ##a=4## or ##a=0## ##a=4## ##4^x=4## ##x=1## ##a=0## ##4^x=0## *no solutions* therefore the correct answer is ##x=1##

Sorry for the super late reply. I decided to continue on with other questions and the next unit before coming back to this. 1) ##\log_2(16) + \log_2(\sqrt{8})## ##\log_2(2^4)(2^3)^{0.5}## ##\log_2(2^4)(2^{1.5})## ##\log_2(2^{5.5})## ##5.5\log_2(2)## ##=5.5## 2) wow I don't know why this...

so the first one would be: ##\log_2(16) + \log_2(\sqrt{8})## ##\log_2(2^4) + \log_2(2\sqrt{2})## and I am not really sure what to do with the square root For the other two questions, is what I have so far correct and I need to take the log on both sides from the point where I am at or is the...

The former I edited the OP to make it a little clearer

Homework Statement Evaluate each of the following expressions without using a calculator. 1) log216√8Solve for the unknown value in each of the following equations without using a calculator. 2) 3(x+4)−5(3x)=684 3) 7(42x)=28(4x) Homework Equations Exponent law for multiplication The...

It's equal to the static force! It's equal to the coefficient of static friction! So it's the static friction coefficient that determines the angle that the boxes will slip. That was a trick question :p Thanks for the help! Thanks for the further explanation

Wow, I don't know how I missed that. 1=2.5tanθ 1/2.5=tanθ θ=tan-1(1/2.5) θ=21.8 The second box...also has an angle of 21.8 degrees. Very surprising. So the angle of slippage is dependent on g and not on m? Or is it entirely dependent on the static force?

hm, is it: 1=196sinθ/78.4cosθ 1=2.5tanθ θ=tan-1(2.5) θ=68.2

FNet is equal to 0 when the box is about to slip due to there being no acceleration. 0=196sinθ-78.4cosθ 78.4cosθ=196sinθ The angle of slippage would depend on m, since m is variable while g is constant. The higher the value of m, the greater the angle the platform would have to be for the box...

Homework Statement At a construction site, a small crane is raising two boxes of nails on a plank to the roof. One box has already been opened and is half full, while the other box is new. The boxes, including the nails weigh 10kg and 20kg, respectively, and are the same size. If the...

Thank you!

Ah, thanks. How did they get the final answer of 48 mi/h?

Homework Statement A locomotive travels on a straight track at a constant speed of 40 mi/h, then reverses direction and returns to its starting point, traveling at a constant speed of 60 mi/h. What is the average speed for the round-trip? Homework Equations avgS = distance/time t = d/40 The...

Ahhh, thank you! I've been scratching my head at this for a few days now. I don't think the Calculus text I am using(Anton Calculus 6th ed.) ever talked about the period of the tangent being π. Or I somehow missed it.

Homework Statement Find the angle of inclination of a line when the slope, m, is equal to -1/2 Homework Equations m = rise/run = tan(φ) φ=angle of inclination The Attempt at a Solution I thought the answer would simply be using arctan on the slope, but my answer gives me -26.565051 degrees...