Recent content by Pablo

I also put the negative value, and it was wrong:

that shouldn't be a problem because there is a margin of error of 2% for answers.

tried doing mWb (both 1.745 and -1.745), but still wrong:

So, I actually got the direction of the magnetic flux through the curved part of the surface correctly (inward). However, this shouldn't matter for the magnitude of the flux as long as I treat the flux of the side a different direction from the flux on the top and bottom. I don't understand why...

I have this problems I am trying to figure out: So I know that $$\int B\, dA = 0 = \phi_{total}$$ $$\phi_{total} = \phi_{bottom} + \phi_{top} + \phi_{side} = 0$$ $\phi_{side}$ must be equal to the other two fluxes, since they are both outwards: $$\phi_{side} = \phi_{bottom} + \phi_{top}$$...

Homework Statement Find moment of inertia of a washer with a hole of radius r/2. Homework Equations Moment of inertia = integral of x^2 dm γ = m / L The Attempt at a Solution I think I can find the moment of inertia of the washer using integral of x^2 dm. So, I know my γ = m / L = m /...

Ok so given that the length is 1 meter, I know λ = 0.2 / 1 = 0.2. I also know the moment of inertia is the integral of x^2 dm from -0.01 to 0.09, equivalent to λ * [ (0.09^3 / 3) - (-0.01^3 / 3)] = 0.000049. This answer is still not correct. EDIT: My bounds were incorrect. I got 0.48, thanks!

Could you explain what this equation means: (m1+m2)R=m1r1+m2r2

Would I use the definition of moment of inertia using calculus or is there another way. I am very confused, and I am not sure how to get started.

How could I use the integral of r^2 dm if I don't know the length of the rod? I can't find λ

Homework Statement The moment of inertia about an axis through the center of mass of a system consisting of two masses 3.0 and 5.0 kg connected by a rod of negligible mass 0.8m long is Homework Equations [/B] I = I1 + I2 The Attempt at a Solution I added all the moments of inertia of the...

Homework Statement A meter stick has a mass of 0.2kg. A small hole is bored in it at the 10cm mark so the meter stick can be hung from a horizontal nail. The moment of inertia of the meter stick around an axis at the 10cm mark is Homework Equations m = 0.2kg I = mr^2 The Attempt at a...

Ah okay, so when they say the frequency they mean the angular velocity right. So it'd be 500 watts.

Wow, I can't forgot to multiply by 2 pi, thanks! I got 0.39Nm :)

Homework Statement Motor runs at a rate of four revolutions/sec has a torque of 20. What is it's power. Homework Equations T = (2π) / w f = w / (2π) w = 2πf P = T * w Power = Torque * angular velocity The Attempt at a Solution [/B] T = 20 Nm f = 4 * 2π = 8π w = 2π * (8π) = 16π^2 P = 20 *...