The moment of inertia about an axis through the center of mass of a system consisting of two masses 3.0 and 5.0 kg connected by a rod of negligible mass 0.8m long is
I = I1 + I2
The Attempt at a Solution
I added all the moments of inertia of the system about the middle (0.4m)
I = m1R^2 + m2R^2 = (m1 + m2) * R^2 = (3 + 5) * 0.4^2 = 1.28
However, 1.28 is not the right answers. Does anyone know where I went wrong?