- #1

Pablo

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- Homework Statement
- The figure shows a closed surface. Along the flat top face, which has a radius of 4.5 cm, a perpendicular field of magnitude 0.18 T is directed outward. Along the flat bottom face, a magnetic flux of 0.60 mWb is directed outward. What are the (a) magnitude and (b) direction (inward or outward) of the magnetic flux through the curved part of the surface?

- Relevant Equations
- Flux on a surface = 0 (by Maxwell's equations)

I have this problems I am trying to figure out:

So I know that $$\int B\, dA = 0 = \phi_{total}$$

$$\phi_{total} = \phi_{bottom} + \phi_{top} + \phi_{side} = 0$$

$\phi_{side}$ must be equal to the other two fluxes, since they are both outwards:

$$\phi_{side} = \phi_{bottom} + \phi_{top}$$

$$\phi_{side} = 0.6*10^{-3} + \pi*(0.045)^2*0.18=1.745Wb$$

However, I am getting that 1.745Wb is the wrong answer. Does anyone know why?

So I know that $$\int B\, dA = 0 = \phi_{total}$$

$$\phi_{total} = \phi_{bottom} + \phi_{top} + \phi_{side} = 0$$

$\phi_{side}$ must be equal to the other two fluxes, since they are both outwards:

$$\phi_{side} = \phi_{bottom} + \phi_{top}$$

$$\phi_{side} = 0.6*10^{-3} + \pi*(0.045)^2*0.18=1.745Wb$$

However, I am getting that 1.745Wb is the wrong answer. Does anyone know why?