Recent content by PhysicsMan999
-
P
Radioactive decay, need to find half life
Okay, so I'm still not really sure how to solve it..plugging in the numbers just keeps on giving me 19.3..- PhysicsMan999
- Post #7
- Forum: Introductory Physics Homework Help
-
P
Radioactive decay, need to find half life
R=rate of decay DN= change in number of nuclei DN=change in time lambda=decay constant N=number of nuclei T1/2= half life I got the equation from a slide my prof has for our lectures.- PhysicsMan999
- Post #5
- Forum: Introductory Physics Homework Help
-
P
Radioactive decay, need to find half life
19.3 days- PhysicsMan999
- Post #3
- Forum: Introductory Physics Homework Help
-
P
Radioactive decay, need to find half life
Homework Statement The number of radioactive nuclei in a particular sample decreases over a period of 26 days to one-fifteenth of the original number. What is the half-life of the radioactive material, in days? Homework Equations R=DN/Dt=(lambda)(N)=(N)(ln2/T1/2) The Attempt at a Solution...- PhysicsMan999
- Thread
- Decay Half life Life Radioactive Radioactive decay
- Replies: 8
- Forum: Introductory Physics Homework Help
-
P
Equivalent resistance in a complex circuit
Figured it out guys! Thanks for the help! Couldn't find an edit button so sorry for the double post just didn't want to unnecessarily take up more of anyones time than needed.- PhysicsMan999
- Post #5
- Forum: Introductory Physics Homework Help
-
P
Equivalent resistance in a complex circuit
Thank you guys! I found R0 and R3 are in series with each other, and so are R1 and R2, and these two series are in parallel with each other. I managed to calculate Req, and the current through R0, but now I'm having trouble calculating the current through R1..I now that parallel resistors are...- PhysicsMan999
- Post #4
- Forum: Introductory Physics Homework Help
-
P
Equivalent resistance in a complex circuit
Homework Statement In the circuit shown, R1 = 0.810 Ω, R2 = 8.10 Ω, R3 = 81.0 Ω, and R0 = 810 Ω. See attachment Calculate the equivalent resistance of the circuit when a 7.70 V power supply is connected between points A and C. Calculate the current through R0 and R1 Homework...- PhysicsMan999
- Thread
- Circuit Complex Equivalent Equivalent resistance Resistance
- Replies: 4
- Forum: Introductory Physics Homework Help
-
P
Solving for distance between plates, diameter of a capacitor
Well, apparently I was entering them in the wrong order..even though it says nothing about the order to enter them in. Thanks!- PhysicsMan999
- Post #5
- Forum: Introductory Physics Homework Help
-
P
Solving for distance between plates, diameter of a capacitor
CAPA says my answers are wrong though! The answers I'm getting are 0.00679 for the distance between plates, and around 0.07 for the diameter..- PhysicsMan999
- Post #3
- Forum: Introductory Physics Homework Help
-
P
Solving for distance between plates, diameter of a capacitor
Homework Statement A 5.02 pF air-filled capacitor with circular parallel plates is to be used in a circuit where it will be subjected to potentials of up to 95 V. The electric field between the plates is to be no greater than 1.40×104 N/C. As an electrical engineer for Live-Wire Electronics...- PhysicsMan999
- Thread
- Capacitor Diameter Plates
- Replies: 5
- Forum: Introductory Physics Homework Help
-
P
Calculate mass of oil droplet between parallel plates
Oh, well that was easy then. Thanks!- PhysicsMan999
- Post #3
- Forum: Introductory Physics Homework Help
-
P
Calculate mass of oil droplet between parallel plates
Homework Statement A droplet of oil, carrying an extra charge of one electron, is held motionless between parallel plates separated by 1.89 cm, with a potential difference of 39.8 kV. What is the mass of the droplet? 2. Homework Equations E=0.5QV C=Q/V The Attempt at a Solution Really...- PhysicsMan999
- Thread
- Mass Oil Parallel Parallel plates Plates
- Replies: 2
- Forum: Introductory Physics Homework Help
-
P
Light rays reflected off vertical mirror (law of reflection)
Ahhh, I see now. Thank you very much! I was trying to solve it a completely different way haha no wonder I couldn't figure it out- PhysicsMan999
- Post #13
- Forum: Introductory Physics Homework Help
-
P
Light rays reflected off vertical mirror (law of reflection)
so the equation i set up was: 15.9-c/11.4= -((c-4.7)/15.9) This is giving me an answer that makes no sense (68.08cm)- PhysicsMan999
- Post #11
- Forum: Introductory Physics Homework Help
-
P
Light rays reflected off vertical mirror (law of reflection)
rise/run. the C-B slope would just be the negative of A-B's slope. I've had the picture for awhile I just can't figure out how to get the right info to solve it- PhysicsMan999
- Post #9
- Forum: Introductory Physics Homework Help