Solving for distance between plates, diameter of a capacitor

Click For Summary
SUMMARY

The discussion focuses on designing a 5.02 pF air-filled capacitor with circular parallel plates for a circuit operating at up to 95 V, ensuring the electric field does not exceed 1.40×104 N/C. The equations used include capacitance (C=kEA/d), electric field (E=V/d), and area (A=πr2). The calculated distance between the plates is approximately 0.00679 m, and the diameter is around 0.07 m. However, discrepancies in answers were noted, prompting a review of unit specifications and significant figures.

PREREQUISITES
  • Understanding of capacitor design principles
  • Familiarity with the equations for capacitance and electric fields
  • Knowledge of unit conversions and significant figures
  • Basic geometry related to circular areas
NEXT STEPS
  • Review the derivation of capacitance formulas in electrical engineering
  • Learn about the impact of dielectric materials on capacitance
  • Explore the significance of significant figures in engineering calculations
  • Investigate the effects of plate area and separation on capacitor performance
USEFUL FOR

Electrical engineers, students in electronics courses, and anyone involved in capacitor design and analysis will benefit from this discussion.

PhysicsMan999
Messages
32
Reaction score
0

Homework Statement



  1. A 5.02 pF air-filled capacitor with circular parallel plates is to be used in a circuit where it will be subjected to potentials of up to 95 V. The electric field between the plates is to be no greater than 1.40×104 N/C. As an electrical engineer for Live-Wire Electronics, your task is to design the capacitor. What is its size? Enter the diameter and the separation of the plates.

Homework Equations


C=kEA/d
E=V/d
A=pir^2

The Attempt at a Solution


I used E=V/d to try and find the distance, then plugged that into the capacitance equation to find the area of the plates, which I then used to find the radius of the circle, which I multiplied by 2 to get the diameter.
 
Physics news on Phys.org
PhysicsMan999 said:

Homework Statement



  1. A 5.02 pF air-filled capacitor with circular parallel plates is to be used in a circuit where it will be subjected to potentials of up to 95 V. The electric field between the plates is to be no greater than 1.40×104 N/C. As an electrical engineer for Live-Wire Electronics, your task is to design the capacitor. What is its size? Enter the diameter and the separation of the plates.

Homework Equations


C=kEA/d
E=V/d
A=pir^2

The Attempt at a Solution


I used E=V/d to try and find the distance, then plugged that into the capacitance equation to find the area of the plates, which I then used to find the radius of the circle, which I multiplied by 2 to get the diameter.
Just what I would have done! Congrats!
 
CAPA says my answers are wrong though! The answers I'm getting are 0.00679 for the distance between plates, and around 0.07 for the diameter..
 
PhysicsMan999 said:
CAPA says my answers are wrong though! The answers I'm getting are 0.00679 for the distance between plates, and around 0.07 for the diameter..
Did the system specify particular units to use? Is it finicky about significant figures?
 
Well, apparently I was entering them in the wrong order..even though it says nothing about the order to enter them in. Thanks!
 
PhysicsMan999 said:
CAPA says my answers are wrong though! The answers I'm getting are 0.00679 for the distance between plates, and around 0.07 for the diameter..
Well, I didn't check your math. I only endorsed your methodology! :smile:
 

Similar threads

  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
3
Views
2K
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
14
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
3
Views
2K