Recent content by PhysicsTest

  1. PhysicsTest

    Engineering Half wave voltage doubler

    Ok just to re confirm my understanding The drop across voltage is Vr= 5V, based on the output polarity o/p it is -5V, Is my understanding correct? please confirm.
  2. PhysicsTest

    Engineering Half wave voltage doubler

    Thank you for all the support. I have a very basic question in the circuit before i start attempting when he shows the negative and positive symbol at the output side as above what does it indicate, is it arbitrary or some logic involved in it? Can you please clarify?
  3. PhysicsTest

    Engineering Half wave voltage doubler

    The input is sine wave vi= Vmsin(wt), the problem is it is increasingly difficult to analyze these kinds of circuits for sinusoidal inputs and with positive and negative portions, most of the time i analyze in the mind without the equations and to remember the states is tough. Do we have simpler...
  4. PhysicsTest

    Engineering Rectifier Meter

    Vrms = 1.11 * Vdc = 1.11*5.01 V = 5.56V
  5. PhysicsTest

    Engineering Rectifier Meter

    Fig: Full bridge rectifier output I calculated above parameters for full wave bridge rectifier, so if Vm of the sine wave increases/decreases the Vdc changes accordingly and the Vrms. The corresponding current is Beyond this i am unable to understand the 1mA and full-scale reading...
  6. PhysicsTest

    Engineering Rectifier Meter

    I am confused with the question it falls under the topic of Rectifier meter, I feel the peak of the sine input need to be provided to calculate the full scale reading of the meter, 1mA is the resolution of the meter. Any hint to solve this problem?
  7. PhysicsTest

    Engineering LR circuit current calculation

    Yes i think i have made wrong calculations it is e^-1 and it comes correctly as 441
  8. PhysicsTest

    Engineering LR circuit current calculation

    In the steady state the current through 100 Ohm path and inductor acts as a short circuit, inductor stores the current equal to as below I = 120/100 = 1.2Amps once the circuit breaker is removed the inductor works as current source the 100 Ohm and 400 Ohm are in series and the current after...
  9. PhysicsTest

    Engineering Full bridge circuit with inductor and resistor

    The above is the circuit i am calculating the inductor current. During the positive half of the sine input D1 and D3 are conducting so the circuit becomes My calculations are as below Are the above equations ok? When transitioning from +Ve cycle to -Ve sine wave does the above equations still...
  10. PhysicsTest

    Engineering Analyzing the inductor current in the circuit

    The above is the problem statement a. I don't understand this question, i am assuming the switch opens and closes and based on that i have to analyze the circuit and find the voltages and currents in the circuit. b. When the switch is closed then the zener diode is reverse biased When the...
  11. PhysicsTest

    To detect 12V using Opamp

    The application is in a commercial vehicle where many ECUs are connected and in case the vehicle is break down, the first thing is to ensure that 12V is coming to all the ECUs, so open each ECU connector identify the pins where 12V shall come, then insert the detection circuit with 2 wires...
  12. PhysicsTest

    To detect 12V using Opamp

    When i thought of comparing with 12V then i got the idea of op-amp, there is no particular reason to use op amp. What range? What precision? I only want to check if 12V available or not, there is no particular requirement of precision. I want to turn on LED if 12V is available and OFF if 12V...
  13. PhysicsTest

    To detect 12V using Opamp

    Yes i will have different circuits, this is basically for field support in the vehicles under break down to get an idea if voltage is in the expected range for persons without technical background.
  14. PhysicsTest

    To detect 12V using Opamp

    I actually mean to put an LED in place of Diode i took wrong part number from LTSpice. I never intended to put a diode.