Analyzing the inductor current in the circuit

[PhysicsTest]

Homework Statement

Inductor based circuit, the problem statement added

Relevant Equations

V = Ldi/dt

The above is the problem statement
a. I don't understand this question, i am assuming the switch opens and closes and based on that i have to analyze the circuit and find the voltages and currents in the circuit.
b. When the switch is closed then the zener diode is reverse biased

When the switch is open, the inductor current and the zener current is 0. But the main concern for me to analyze the circuit is there is no resistor available for voltage drop and i am not able to analyze the circuit.

 

[Baluncore]

The inductor current is limited by inductor series resistance, or by limiting the on-time of the switch.

The zener will only conduct momentarily after the switch turns off, as the inductor voltage is reversed while the current falls to zero.

A diode across the inductor will limit the inductor reverse voltage, so it will take longer to turn off. The zener allows a greater reverse voltage, so the inductor current falls faster.