Recent content by physx_420

This isn't a homework question but if it belongs in another thread please tell me so I can switch it. I was just wondering if there is an "agreed-upon" speed that an electron would travel in say a vacuum? I understand that one can continue adding energy until the electron reaches very nearly...

Firstly, if it is frictionless then it is not a friction problem lol. What other equation do you think you need to solve this?

Word. :cool:

If you think of it from the point of view of the kid's hands then there is some motion to the kid. He doesn't just catch it with his hands and they (his hands) stay still, rather they move back a certain distance, albeit a relatively small distance. So yes, the ball does do work on the kid...

That sounds right to me.

displacement = x(final)-x(initial) s = 0-132 When you used 52 m/s (which was your initial velocity) for your motion equation, you get an initial position.

Did you use a positive acceleration or a negative acceleration? Always remember which way you set up your coordinate system (i.e. down is negative and up is positive.) If you used (-8)m/s for the velocity than we assume down is negative.

1 cubic centimeter = 1.0 × 10-6 cubic meters. When you use a million, you should get: 5.01E-17 Pa, when converted, you end up with 4.8546E-22 atm.

"Find the displacement of the ball." Since you throw the ball straight up and it comes back down to where you initially threw it from, then I believe the displacement should be zero. It would be like running a lap around the track. Sure you have ran a 1/4 of a mile but your total displacement...

set bernoulli's equation equal to zero and solve for v. Now since this is an ideal fluid the velocity of fluid flowing through point a, 1.84m, is going to be equal to the velocity of fluid through point b, 0.45m. So you then use the equation for volume flow rate which is dV/dt= A1v1= A2v2, where...

http://www.intmath.com/ This is an excellent site for what you're looking for...just scroll down to "Higher Calculus" and you should see "Fourier Series."

ah so that's where I went wrong...I tried u substitution but I used u=sin2x instead of u=2x. thanks mark44.

Homework Statement \int sin(2x)dxHomework Equations I know the integral of sin(x)dx = -cos(x) + CThe Attempt at a Solution What I did was to say that the integral is -cos(2x) +C, which isn't the correct answer...I should have gotten -1/2(cos(2x)) +C. I can see that this is the correct answer...

in M. Alcubierre's equation the "s" in the superscript of "v and r" are supposed to be subscripts, I just couldn't get them to work. btw

ds^{2} = -c^{2}(1 - \frac{2Gm}{c^{2}r})dt^{2} + (1 - \frac{2Gm}{c^{2}r})^{-1} dr^{2} + r^{2}d\Omega^{2} This equation was posted on a different website and the O.P said:"Applying variational principles to that metric describes a black hole!" I was wondering if anyone could explain it a...