Recent content by pivoxa15

Obviously, one cannot do a direct measurement as one cannot reverse time. But realistically heavy weight training in early teen years compared to no weight training could cause a little difference of maybe up to an inch, no more.

But do they use weights everyday? Most Likely not? Do they start lifting weights at 14? Probably not?

If I could live my teen years again, I wouldn't do any lifts nor take any supplements. I'd do moderate amount of sport for enjoyment only, not to improve my physical appearance or anything. I'd say after 21 is usually a safe age to do weights. However, to be very safe, after 24.

He seems good. Maybe you can study with him for a Phd so you don't have to travel overseas? Why didn't you do honours with him?

After I created this thread, I realized the conjecture was false.

Homework Statement Conjecture: If K=a union of subsets of G with K open then each subset in the union is open The Attempt at a Solution Can't really see the proof. In fact it's false as any non discrete topology have open sets which are a union of subsets whch may not be open.

Which string theorist?

RIght, I found a proof of it using product topology and component mapping, pi which is open.

To be more specific, I had a sequence a_m/b_m where a_m and b_m in the limit is 0. However they are not functions so can't use that rule which I can't spell, l'hospil's rule?

But do all f_g have to be continuous maps? It isn't implied from the axioms for a topological group.

Under what circumstances are open maps continuous and vice versa?

In which case it would be in a compact space. All cauchy sequences in a compact space converge.

Okay, good point. I'll be more specific. I was thinking of limits of sequences only. Or are all limits sequences in which case I haven't narrowed down anything?

I realized that after posting. I may have remembered under some circumstances, open sets are mapped to open sets. What is this circumstance?

Homework Statement Prove: a topological group is discrete if the singleton containing the identity is an open set. The statement is in here http://en.wikipedia.org/wiki/Discrete_group The Attempt at a Solution Is that because if you multiply the identity with any element in the group, you get...