Open Subsets of a Union: A Conjecture

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Homework Help Overview

The discussion revolves around a conjecture regarding open sets in topology, specifically addressing the claim that if K is a union of subsets of G and K is open, then each subset in the union must also be open. Participants are exploring the validity of this conjecture and its implications in various topological contexts.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Some participants question the validity of the conjecture, noting that it appears to be false in non-discrete topologies. Others provide examples of unions of non-open sets that result in open sets, prompting further exploration of the assumptions underlying the conjecture.

Discussion Status

The discussion is active, with participants sharing counterexamples and questioning the original statement. There is an acknowledgment of the conjecture's falsehood, but no consensus on a definitive resolution has been reached. Various interpretations and examples are being explored.

Contextual Notes

Participants are discussing the implications of the conjecture in the context of different topologies, particularly focusing on non-discrete topologies where the conjecture does not hold. There is a recognition of the need for clarity regarding the definitions of open sets in these contexts.

pivoxa15
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Homework Statement


Conjecture: If K=a union of subsets of G with K open then each subset in the union is open

The Attempt at a Solution


Can't really see the proof. In fact it's false as any non discrete topology have open sets which are a union of subsets whch may not be open.
 
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How do you expect to see the proof if you already know that the statement is false?!
 
Or consider the classic example where one takes the reunion of the non-opens sets [1/n,+infty) and get the open sets (0,+infty)
 
You can practically create a counterexample for any topology except that of the discrete topology.
 
quasar987 said:
Or consider the classic example where one takes the reunion of the non-opens sets [1/n,+infty) and get the open sets (0,+infty)

Why not just take the union of 0 and (-1,1). We get the open set (-1,1) but the point 0 is closed.
 
morphism said:
How do you expect to see the proof if you already know that the statement is false?!

After I created this thread, I realized the conjecture was false.
 

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