Recent content by pmart491

Homework Statement Draw the structural formula for a three-monomer segment of poly(1,3-butadiene) in which addition is 1,2 for the middle unit and 1,4 for the outer units, with double bonds Z. Homework Equations Markovnikov's rule: H goes to the Carbon with the most H's The Attempt at a...

Thanks for the great advice! I like organic the best so far (only had organic and chem 1)

Yea my chem teacher told me he never got above a 60 on a test in p chem and he still has no idea what its about. I'm taking organic now and its pretty easy for me.

Hey, I'm going to college next year and I am majoring in chemistry. Just wondering, what chemistry class was the most difficult to understand?

one of the priorities is wrong. take a look at what is bonded DIRECTLY NEXT TO the first carbon

well i think i got it based on the half reaction, there are 5 times as many Cl- ions as there are MnO4- ions. therefore there are 5 times as many moles of NaCl than there are moles of KMnO4. 5 x .00136=.0068moles NaCl .0068moles NaCl/.0186L NaCl=.372M NaCl

Ok I got 10Cl- + 16H+ + 2MnO4- -> 5Cl2 + 2Mn2+ + 8H2O Next I did 13.6mL KMnO4 x .1M = .00136moles KMnO4 what i don't understand is how to find moles of NaCl through the half reaction

Homework Statement What is the molarity of a NaCl solution if 18.3mL of the solution reacted with 13.6mL of 0.1M KMnO4 based on the following unbalanced redox reaction in an acidic solution? Cl- + MnO[SIZE="2"]4- yields-> Cl[SIZE="2"]2 + Mn2+ The Attempt at a Solution I did the...

yea so itd be 1.62 right?

or do u have to change moles of HCl back to molarity? .012moles HCl ------------- .5L total =.024 pH=-log(.024)=1.62

is it .36-.348=.012 moles of HCl which = number of H+ ions? pH=-log(.012) = 1.92?

Homework Statement If you mix 200mL of a 1.8M HCl solution with 300mL of a 1.16M NaOH solution, what will be the pH of the solution? The Attempt at a Solution Well I am really lost with this problem. I am pretty sure you need to convert each to moles. .2L HCl x 1.8moles HCl...

this is the ICE chart i have so far P H2 I2 HI I 59.19atm 118.39atm 0atm C (1-x) (2-x) x^2 E 59.19(1-x) 118.39(2-x) x^2 x^2 --------------------------- 59.19(1-x) times 118.39(2-x)when i do that i get x=square root of 707757.5 - 1061636.25x + 353878.75x^2

HI=x^2 H2=(1-x) and I2=(2-x)...I just have to plug in the numbers now and see what i get.

oh so its x^2 and not 2x, thanks