Understanding E and Z Isomerism in 3-Isopropyl-2-Heptene

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The discussion centers on the isomerism of 3-isopropyl-2-heptene, specifically whether it is classified as E or Z. There is a disagreement regarding the priority of the groups attached to the double bond, with one participant asserting that the book's classification as Z is incorrect. They argue that the left side of the molecule clearly shows which group has higher priority, while the right side's priority is debated due to the length of the carbon chain. The conversation emphasizes the importance of examining the groups directly bonded to the first carbon for accurate classification. Ultimately, the correct identification of the isomer hinges on understanding these priority rules.
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Is this the E or Z isomer of 3-isopropyl-2-heptene?

1538enn.jpg


My book says Z, but I would think it's E. On the left, there is no doubt which group has higher priority. I would believe that on the right side, the lower group has the higher priority because there is a longer chain of C-atoms.
 
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one of the priorities is wrong. take a look at what is bonded DIRECTLY NEXT TO the first carbon
 
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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