Polymer: Draw Structural Formula 1,3-Butadiene Z

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SUMMARY

The discussion focuses on drawing the structural formula for a three-monomer segment of poly(1,3-butadiene) with specific addition patterns: 1,2 for the middle unit and 1,4 for the outer units, featuring double bonds in the Z configuration. The participant references Markovnikov's rule, which states that hydrogen atoms will bond to the carbon with the most hydrogen atoms. The challenge lies in accurately depicting the bonding locations for the specified addition types, particularly distinguishing the middle unit from the outer units.

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Homework Statement



Draw the structural formula for a three-monomer segment of poly(1,3-butadiene) in which addition is 1,2 for the middle unit and 1,4 for the outer units, with double bonds Z.

Homework Equations



Markovnikov's rule: H goes to the Carbon with the most H's

The Attempt at a Solution



Not too sure on this one.

1,3 butadiene is CH2=CH-CH=CH2

My attempt is posted in the picture

organicchemproblem.jpg


I know how to make it E or Z its just I do not know where the chains become bonded and how.
 
Last edited:
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1,2 was for the MIDDLE unit, not the leftmost one.
 

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