Polymer: Draw Structural Formula 1,3-Butadiene Z

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Homework Statement



Draw the structural formula for a three-monomer segment of poly(1,3-butadiene) in which addition is 1,2 for the middle unit and 1,4 for the outer units, with double bonds Z.

Homework Equations



Markovnikov's rule: H goes to the Carbon with the most H's

The Attempt at a Solution



Not too sure on this one.

1,3 butadiene is CH2=CH-CH=CH2

My attempt is posted in the picture

Handwritten skeletal structure of a three-unit polybutadiene segment: a CH3-CH(CH2-CH=CH-CH2-CH=CH-CH3) branched chain drawn with carbon chain lines and double bonds.


I know how to make it E or Z its just I do not know where the chains become bonded and how.
 
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