Finding pH given molarity and volume problem

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Discussion Overview

The discussion revolves around calculating the pH of a solution formed by mixing hydrochloric acid (HCl) and sodium hydroxide (NaOH) solutions, focusing on the stoichiometry of the reaction and the resulting concentration of hydrogen ions.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant presents the initial problem and attempts to calculate the moles of HCl and NaOH based on their molarity and volume.
  • Another participant points out the need to determine which reactant is in excess and by how much.
  • A participant calculates the excess moles of HCl and proposes a pH value based on the remaining H+ ions.
  • There is a suggestion to convert the excess moles of HCl back to molarity to find the pH accurately.
  • A participant emphasizes that for calculating pH, the concentration of hydrogen ions should be considered as molarity.
  • Subsequent replies confirm the calculated pH value of 1.62 based on the molarity derived from the excess moles of HCl.

Areas of Agreement / Disagreement

Participants generally agree on the calculated pH value of 1.62, but there is some uncertainty regarding the steps taken to arrive at that conclusion, particularly in the conversion from moles to molarity.

Contextual Notes

The discussion does not resolve the potential confusion regarding the conversion of moles to molarity and the implications of strong acid behavior in solution.

Who May Find This Useful

Students working on acid-base chemistry problems, particularly those involving pH calculations and stoichiometry in reactions.

pmart491
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Homework Statement


If you mix 200mL of a 1.8M HCl solution with 300mL of a 1.16M NaOH solution, what will be the pH of the solution?

The Attempt at a Solution


Well I am really lost with this problem. I am pretty sure you need to convert each to moles.

.2L HCl x 1.8moles HCl
------------------
1L HCl

.3L NaOH x 1.16 moles NaOH
---------------------------
1L NaOH


HCl=.36moles

NaOH=.348moles

HCl + NaOH -> NaCl + H2O

not too sure where u go from there
 
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The acid and the base react 1:1, so which is in excess, and by how much?
 
is it .36-.348=.012 moles of HCl which = number of H+ ions?

pH=-log(.012) = 1.92?
 
or do u have to change moles of HCl back to molarity?

.012moles HCl
-------------
.5L total

=.024

pH=-log(.024)=1.62
 
HCl in aqueous solution is strongly ionized, or completely ionized for most practical purposes. For pH, you want the hydrogen ion CONCENTRATION AS MOLARITY..., and then find the negative logarithm.
 
Last edited:
yea so itd be 1.62 right?
 
Yep, 1.62 it is.
 
Welcome back, Borek! You were missed.
 
chemisttree said:
Welcome back, Borek! You were missed.

:blushing:

I am planning to spend some time here now ;)
 

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