Recent content by praveenpandiyan

yea h .yeah ,.. I am seeing it ,anyway thanks

i didnot mean that way. i value you all. but i was in a hurry,, needed approach or formula that i miss.exams coming up.

let original length be L ... but i have no idea how to find length btw consecutive section after load is applied.

only problem I am facing is its E value .. at dx E= E1-((E2-E2)/L)*x .im bit confused.

well then the material vary at every point (as u said).. so i need to find extension at given small dx. and integrate from 0 to L . is that right

yes sir .tensile stress =P/A. and strain = dL/L. .by hookes law E=stress/strain giives dL= PL/AE

centimeter by centimeter?. well threre must be some other way, like its going to be triangular profile with one end E1 and other end E2.. is that possible to find equivalent E acting on rod ..

Homework Statement see attachement Homework Equations dl= PL/AE The Attempt at a Solution as you see here my youngs modulus E varies linearly. i doubt that adding up E1 &E2 wld give solution.. any help?

i found other boundary condition too ..beam shear stess (tou)xy=o at y=(-h &=+h)..thanks anyway ..

Homework Statement For (fi)= (b/6) x*y3 +C*xy show that simply supported beam of 2L loaded concentrated load at mid span.,the stress function satisfy loading condition is (fi) .treat concentrated load as shear stress suitably distributed to shoot this function. so that intergtal of limit (h to...

thanks Nas .. i got the solution...sinusoids having frequencies in integer multiple of (f) have net freq (f) when addded together..when i consider by t=1/f ..its pretty clear final net freq occur only after first signal ..so answer is P

well. i think bulk modulus =direct stress/ vol strain .here pr stress

resultant frequency X=p. Any IDEA how they got it

yes sir but I don't hv known limits in Grapically ..only freq . so by trignometricaL relation i tried it( as u said) ..with sin A+sinB=(1/2)*sin((1/2)(A+b))*Cos((1/2)(A-B)). . i get in the form sin*cos+Sin(C) AND no use of sin A*cosB.. how to proceed here

yes . take moment about A. consider moment contribution at C ...both X and Y.. u need vertical distance of load that act from base.. that would be 1 . so that's it