Recent content by Pyrokenesis

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    What is the derivative of a complex function?

    Thanks TheElectricChild. Ebolamonk3y, I think MiGUi, just got the functions mixed up, an easy mistake to make. You are right, g(x)=z+i... g(x)^2=(z+i)^2, therefore, the answer is: 2i/(z + i)^2, which after substituting i for z, yields: -i/2.
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    More Complex Complex Analysis

    More "Complex" Complex Analysis I have another problem that has eluded me for days and I'm sure I'm close. If anyone can help, please nudge me in the right direction. Consider the mapping w = u + iv = 1/z, where z = x + iy. Show that the region between the curves v = -1 and v = 0 maps into...
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    What is the derivative of a complex function?

    Cheers Thanks. I was being stupid, that formula and fact that differentiation rules for real calculus and complex calculus is the same, was on the previous page to that question.
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    What is the derivative of a complex function?

    I am having trouble with the following question, any help would be blinding. Find the value of ther derivative of: (z - i)/(z + i) at i. I tried to use the fact that f'(z0) = lim z->z0 [f(z) - f(z0)]/z - z0. I also tried using the fact that z = x + iy and rationalising the denominator...
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    Solving an Eigenvalue Problem for Large n Matrix

    Thanx bro, I know, its a tough subject, cheers for the link. Now that all other coursework is out of the way I will crack on with this and post my findings when I find something. Good luck with your course as well, cheers, Dexter
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    Do photons effectivley travel instantaneously?

    Thanx guys, I've read a bit more on the subject, and if he couldn't see his image then as I understand it he would know the speed he was moving at without having to look outside his own frame. This violates the principle of relativity. Makes sense!
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    Do photons effectivley travel instantaneously?

    Do photons effectivley travel instantaneously? If not then the question posed by Einstein "If I travel at the speed of light and hold a mirror in-front of my face, do I see a reflection?" has the answer, no! Although I'm not positive why but would say that because your in the same frame of...
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    L2 transformation reduces to the L1 transformation

    Sorry. Yes standard configuration is when both reference frames move in the direction of the x-axis. Thanks I think I can solve it now.
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    L2 transformation reduces to the L1 transformation

    The L2 transformations are as follows: r' = r + γv^[(1 - 1/γ)(r.v^) - βct]; ct' = γ(ct - r.β); where β = v/c & v^ is the unit vector in the direction of v. The L1 transformations are: x' = γ(x - βct); y' = y; z' = z; ct' =...
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    L2 transformation reduces to the L1 transformation

    Hello. I am having trouble answering the following question: "Show that the L2 transformation reduces to the L1 transformation when the two reference frames are in standard configuration." Am I wrong to assume that r = xi + yj + zk Any help would be beautiful! Thanx much
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    Solving an Eigenvalue Problem for Large n Matrix

    I am having trouble with the following question. (Just hoping to get some guidance, recommended texts etc.): "Consider an eigenvalue problem Ax = λx, where A is a real symmetric n*n matrix, the transpose of the matrix coincides with the matrix, (A)^T = A. Find all the eigenvalues and...
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    Special Relativity and radioactive nucleus

    Thanx for all your help. Should have seen it all along!
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    Special Relativity and radioactive nucleus

    Sorry, didnt see your last reply. Our equations look similar (apart from a difference in sign, mine is probably wrong then) and obviously v is the speed of the nucleus which is the moving frame.
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    Special Relativity and radioactive nucleus

    I have an equation: u(y)' = u(y)/(gamma)(1 - u(x)v/c^2). Is this the equation?
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    Special Relativity and radioactive nucleus

    Yes I see that now I was just being slow of brain, however I have an answer now for v using just the values of u(x) and u(x)', and the transformation velocity equation for u(x). Is that the velocity of the S' frame and is it needed?
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