Recent content by Raza

So we all have electrical charge? and so does every object in the world, but it can be either positive or negative, or sum up to 0? In the Wikipedia, it says that there's only two types of charges; positive or negative.

Do you and I have a charge?

Hello, I was trying to understand what light really is in definition and that means that I have to understand more basic stuff. I am trying to figure out what charge is and what is the difference between energy and charge? On Wikipedia, I read that "Electric charge is the physical property of...

If 300kg object moved backward at the rate of 2.5m/s, then how far did a 75kg object move back? (2.5/75)*300

Okay, I had this question in my exam and after being verified by other people, I think I got it correct. 95937 mod 2537 = 95512 mod 2537 x 95256 mod 2537 x 95128 mod 2537 x 9532 mod 2537 x 958 mod 2537 x 951 mod 2537 So now you do the mod from the power of 1 at . 951 mod 2537 = 95 952 mod...

how did my friend do it? how did he break down the huge number? ' basically how do you compute 95937 mod 2537

lol, you are in my security class. prolly Ian.

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Homework Statement 95937 mod 2537 Homework Equations None The Attempt at a Solution Here's what my friend did: How do I do this? and how did he do this?

Thank you, Mark44, I realize that it would be too hard to go through that.

Hello, I know that it could be done with simple substitution. I was just curious of why it won't work by IBP. Also, because I've seen ⌠tanx = ln|secx| and as -ln|cosx| I thought that ⌠cotx = ln|sinx| would also be -ln|cscx| was trying to prove that maybe it is also equal to -ln|cscx|.

http://www.physicsclassroom.com/class/1dkin/u1l6b.cfm

When I didn't have glasses and I sometimes had trouble what was on the board, I had to do that (finger going across my eyes) to see what was written. I don't know how it works, but it works. The way I see it, it's like the object is blocking quanta from coming to your eyes, the pressure on...

Homework Statement find ⌠cotx using integration by parts with using u= 1/sinx and dv= cosx Homework Equations cotx=cosx/sinx The Attempt at a Solution u= 1/sinx and dv= cosx dx du = -cotxcscx dx v= sinx ⌠udv = 1 + ⌠sinx cotx cscx sinx and cscx cancel out. ⌠cotx = 1 +...

Where did you get this formula? I thought that 3/4 + 3/4 = 6/4 = 3/2 = 1.5 But obviously, you did something differently because it's speed of light we are dealing with.