Recent content by Reallyfat

Thanks, I haven't learned this at all, actually. That should explain why it won't do the same thing if I put it in a core. Do you know why the fuse on the extension plug blew, rather than the one on the coil plug?

Hi, I'm trying to wire a transformer which steps my mains voltage (240VAC) down. I just finished wiring the the primary to the plug, and thought I should test my connections by plugging it in. The coil was not inside the core or near the secondary, it was just lying on a piece of paper. I...

The reflecting surface is initially at rest. And the incident light will cause some change in momentum to the incident area, but that is going to be opposed by other nearby atoms in the surface, which will bring it to rest again if it should move.

I know that a change in frequency is a change in energy, that is the point I am trying to make here. That frequency should change even without the Doppler effect. Which question have I not answered correctly?

The reflecting surface: yes, though that change in frequency would be due to the Doppler effect and not the conservation of energy explanation that I am trying to point to. What I would like to know is this: If a ray of light were to reflect off any surface, would the total energy of the...

That would be variable from mirror to mirror and surface to surface. I'm not looking for a calculation to a specific case though, but just a general explanation. If I had a glass block, for example, from which an incident white ray was reflected, would the reflected ray not have a frequency...

We would have to use a frame where the reflecting surface would have an initial momentum of zero, if we were to try and apply this in a realistic situation. Its momentum would have to change, of course, even if very slightly.

Note that I am not addressing only specular reflection here, but both kinds. Anyway, so if I had light of a certain frequency incident upon a surface, will the light that reflects off that surface also have the same frequency? That would imply that it had retained the full 100% of its energy...

This is known as the baryonic asymmetry - as yet, an unanswered question in physics. It has been proposed that massive bosons may have played a role in it, but no sound theories exist as of yet.

Not while it's in space, but upon collision with a screen, perhaps?

As far as I know, Feynman never attempted the actual experiment with observation for photons. I do not believe such equipment was even available. What he could have done, however, was carry the experiment out with high-energy photons in a cloud chamber, thus revealing their tracks. This should...

But that doesn't make sense. You are trying to imply that if I know a source which emits photons in a certain direction and with a certain frequency, I can never know its momentum and position with infinite certainty even if I know when it was emitted! If I know its momentum with exact...

More of a thought experiment, really. Say we remove the filter. Correct me if I am wrong here: Using my extremely-high-precision-shutter, I can localize my photon with an uncertainty of 0, right? Now, would that mean that my uncertainty in momentum has actually gone up to infinity? Being a...

Well, I obviously am, aren't I? My purpose is to find a possible scenario that doesn't fit with this principle. So what do you think - If we had a mechanism that could emit an electron at a particular chosen velocity, could the uncertainty principle be violated? This takes place in a vacuum...

Hm. Alright then. Perhaps I should consider something else. Why not a single electron? We know electron mass. Can we not choose a velocity with which to emit it? That should give us a precise momentum, as well as a position determined by multiplying the speed of the electron by the time since...