Recent content by RockenNS42

I need it for my physics class, we are running the plotting tool Grace. I had it running on my computer (with some help) So I think I may have downloaded everything I need to run grace, but when I open up the cygwin terminal and type in xmgrace it says /usr/bin/xmgrace.exe: error...

ok well the wave equation is y(x,t)=Asin(k(x-vt)+δ) we know A, v,and k and we can sub them into get y(x,t)=0.02sin(2.8(x-22.4t)+δ) and expand y(x,t)=0.02sin(2.8x-62.8t+δ) to get δ we take the conditions given @t=0, y=.01m x=0m( its at the driving end, I left this out in my initial...

I was just having the biggest brain fart ever, I figured it out after I posted, but didnt have a chance till now to comment

in the form y(x,t)=Asin(k(x-vt)+δ) where p is the phase angle A is .02m v=22.4m/s t=0.1s k=2.80 wavelengh= 2.24m at time t=0, the dispaclement(y) is 0.01m with dy/dt is negative Im not sure how to findδ

That. Little was enough! I got it thanks :)

it the text it has one heres a pic of the page

1. Homework Statement A U-tube has vertical arms of radii 'r' and '2r', connected by a horizontal tube of length 'l' whose radius increases linearly from r to 2r. The U-tube contains liquid up to a height 'h' in each arm. The liquid is set oscillating, and at a given instant the liquid in the...

the questions been resolved, thanks I went to see the prof

Im sorry that I am having a hard time understanding so df(x)/dx * Δx the dertivie of x^2 is 2x so its 2x*1.000001 f(1.000001)≈2 Δx +1? if Δx =0.000001. so 2*0.000001 +1? f(x) = (1 + x)^2 f'(x)= 2(1+x) for very small values of x this would be 2, no?

ok so x + Δx = 1.000001 and i really have no clue. f(x+Δx)≈2 Δx +1 f(1.000001)≈2 Δx +1? or am i still even using the right thing?

i ment Δx = (1.000001 -1)/2 which is really small? getting close to zero...

Ok so v= πr2 h the h would be the length, I think. the r2 has to do with the raduis, but that's changing, doesn't chaning things like that have something to do with the ∫?

does that mean that x+Δx is the 1.000001? Making Δx (1.000001 -1)/2 ?

I do see that f(x) = x^2 it would be 1 and in f'(x) it would be 2 f(x+Δx)−f(x)≈df(x)/dx Δx f(x+Δx)−1≈2 Δx f(x+Δx)≈2 Δx +1 Like I don't understand how to use the formula maybe? I understand what a derive is and how to plug and chug numbers, just not this formula or even how it applies...

ok f(x+Δx)−f(x)≈df(x)/dx Δx so 2x*Δx ? I do not understand what the Δx even is in this case