Recent content by RPinPA

That's just noticing that for any number, ##x^{3/2} = x^{1 + (1/2)} = x * x^{1/2}## So ##(y - 2)^{3/2}## can be written as ##(y - 2)(y - 2)^{1/2}##. Oh, I see another issue. ##(y - 2)^{3/2}## shouldn't be under the radical sign. You had ##\sqrt{(y - 2)^3}##. That's equal to ##(y - 2)^{3/2}##...

Yes, I'd say that the multiplicative identity can be used here. If C = 1, the multiplicative identity, then B x C = B Using the definition of division (y is defined to be z/x with x nonzero, if xy = z), then C = B/B.

I think that just makes it a truncated normal.

Write ##i## as ##e^{i\pi/2}##. Then it's clear that ##\left |i^n \right | = \left | e^{i n \pi/2} \right | = 1## for any real n.

You've just discovered by combinatorial optimization is considered a "hard" problem. In general searching for an optimum integer solution takes a very long time as you have discovered. If you can accept merely a pretty-good solution, there are heuristics you can apply. One of them is...

For a similar analysis with squirrels, check out this hilarious video by Mark Rober, an engineer with way too much time on his hands. Link should take you to 15:59 where the discussion begins.

It has nothing to do with the specific data. If you have something that goes from 0 - 1 with 0 being weakest and 1 being strongest, you can chop it any way you like and define any names you like to break that up into ranges from "weakest" to "strongest". You defined categories for |r|: 0 - 0.5...

Nothing wrong with sharing your solution, but if you post in a forum and expect people to respond, it's generally customary to indicate what sort of response you're looking for.

OK, that seems valid. So now you need to perform the integral. What was your question? I'll also note that you could have just observed that ##A_2## is a square of side 2, therefore its area is 4.

Are you asking for an expression for the angular momentum of a disk where the rotation axis is not perpendicular to the disk? Your drawing is not clear. Are ##\omega_x, \omega_y## and ##\omega_z## the cartesian coordinates of ##\vec\omega##? How are ##I_x##, ##I_y## and ##I_z## defined? Can...

I'm struggling to understand your problem. What are the "grid positions" you're referring to? I believe EIG does not return the eigenvalues / eigenvectors in any particular order. You may be comparing to a plot where they are sorted in order of descending eigenvalue magnitude. Perform that...

You want a different form of the sine wave, sin(k(d - d0)) A positive value of d0 will shift the sine wave left by d0 days, a negative value will shift it right. I'm not sure which of those cell references corresponds to the day number d. But basically you want the shift to be grouped with the...

As a counterexample, when I took Real Analysis, I found drawings to usually be the key to working out a proof. Even though they were proofs of fairly abstract things generalized to n-dimensional spaces, a little doodling in 2-D was often enough to show me why the theorem was true. In the case of...

There's no reason for a "because". (1, 2) is notation for the set of points such that 1 < x < 2. You don't have to do any deduction. This is called interval notation. Square brackets are commonly used for intervals that include the endpoints. If I say x is in [1, 2], that means x lies in the...

I think you may be doing something like this: - many physicists are introverts - therefore physics causes introversion - or in order to succeed in physics, I must become an introvert Those aren't logical deductions. I personally am extremely introverted. That doesn't mean I hate people or even...