Recent content by RTW69

Does K.E.= 1/2 X M X V2 look familiar?

You will also need to know something about the outdoor temperatures where the building is located. An average winter outdoor temperature is a start but not very accurate, average temperature by month would be better, heating degree days are also used, bin data is also used.

There is a lot of information related to this problem on the net just Google "Water Rocket Differential equations". This is a very common undergraduate engineering lab

Isn't the equation kave=3/2*N*kb*T where N is the number of molecules in the vessel? What is N? I'm guessing it isn't 1.

Actually you know the velocity of the electron in the y-direction it is 0 m/s, therefore v=1.74*10^7i+0j m/s and a=7.84*10^14i+1.5*10^15j, you have solved for t and you know vi and ai so you can solve for y. You are almost there.

Guess I can't copy mathematica text into the message box

c=Subscript[p, 1]*Subsuperscript[v, 1, 2] but work = \[Integral]p \[DifferentialD]v =\[Integral]c/v^2 \[DifferentialD]v = c \[Integral]1/v^2 \[DifferentialD]v the rest is basic calc. I believe the answer units is KJ/Kg

c=p1*v12 but work=∫p*dv=∫c/v2*dv=c∫dv/v2 the rest is basic calculus. The answer units should be kj/kg

You can cool yourself in a sauna by sweating. If you were wearing a coat in a sauna you would probably over heat and die.

OK, Final:m*g-3/4*N=m*Vf^2/r

Homework Statement Determine the speed with which the Earth would have to turn to rotate on its axis so that a person on the equator would weigh 3/4 as much Homework Equations VT=r*ω ; Vi=469 m/s is tangential velocity of earth ƩF=M*ac=m*Vt^2/r The Attempt at a Solution The...

It doesn't. It becomes sqrt((m/k)v2 + x2)

Google "Wind Power" If you look at the velocity profile of a fluid moving across a flat horizontal plate you will see why elevation above the surface is important.

I would start by assuming a cylinder of uniform temperature and convection as being the most dominate heat transfer mechanism and see where you end up time wise. Then perhaps you look at evaporation effects from the open glass. If that doesn't get you close things get ugly.

Get 1.5 oz of ethyl alcohol, 4 oz of coke, 3 oz of ice. Mix in a glass cup. Get thermometer and watch. Record the time to get to room temperature. This process will be more accurate than trying to model the heat transfer.