Fundamental thermo systems problem

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SUMMARY

The discussion focuses on calculating the work done during the reversible expansion of a fluid in a cylinder, transitioning from a pressure of 3 bar to 0.6 bar, following the relationship p = c/v². The work done is derived using the integral of pressure with respect to volume, leading to the conclusion that the work done is 29.82 J/kg out of the system. The calculation utilizes basic calculus principles and the ideal gas law, specifically P1V1 = P2V2, to establish the necessary relationships for solving the problem.

PREREQUISITES
  • Understanding of thermodynamic principles, particularly the ideal gas law.
  • Familiarity with calculus, specifically integration techniques.
  • Knowledge of pressure-volume relationships in thermodynamic systems.
  • Basic understanding of specific volume and its implications in fluid mechanics.
NEXT STEPS
  • Study the derivation of work done in thermodynamic processes using integrals.
  • Learn about the implications of specific volume in fluid dynamics.
  • Explore advanced topics in thermodynamics, such as the first and second laws of thermodynamics.
  • Investigate the applications of Mathematica for solving complex thermodynamic equations.
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Students and professionals in mechanical engineering, thermodynamics enthusiasts, and anyone involved in fluid mechanics calculations will benefit from this discussion.

kik369
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1. Unit mass of a fluid at a pressure of 3 bar, and with a specific volume of 0.18 m3/kg, contained in a cylinder behind a piston expands reversibly to a pressure of 0.6 bar according to the law p = c/v2, where c is a constant. Calculate the work done during the process.
2. P1V1=P2V2
3. I know that the answer is 29.82 J/kg out of the system, but how to get it?
 
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c=p1*v12 but work=∫p*dv=∫c/v2*dv=c∫dv/v2 the rest is basic calculus. The answer units should be kj/kg
 
c=Subscript[p, 1]*Subsuperscript[v, 1, 2] but work = \[Integral]p \[DifferentialD]v =\[Integral]c/v^2 \[DifferentialD]v = c \[Integral]1/v^2 \[DifferentialD]v the rest is basic calc. I believe the answer units is KJ/Kg
 
Guess I can't copy mathematica text into the message box
 
Thank you! I'll go through this tomorrow. I've been working on these problems the whole day. It is time for me to take a break. I appreciate the reply.
 

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