Recent content by RyanSchw

Homework Statement This should be a really easy circuit, but I need to see if I have it done right. 1V source, 1A source and a 1 Ohm resistor in parallel (forgot to write the 1 Ohm resistor on the image.) Find the power of each element. http://img403.imageshack.us/f/circuit1.jpg/...

For the first, I think more algebra is required than substitutions, you just need to be cleaver.

For the second problem, have you considered Polynomial long division, or do you have to use a substitution?

I'm still not sure that I know what I'm doing, but sticking to two loops helped; I have the correct answers now. This is such a headache, you guy have no idea how long I've been stuck on that simple little problem, onto the next one. Thanks for the help.

Homework Statement Sorry for edit, accidentally posted. Circuit is show in my attachment. I have 3 loops with three unknown currents. 8 Ohms of resistance down the left side. 6 Ohms of resistance and a 4V battery down the center. 4 Ohms of resistance and a 12V battery down the right side. I...

http://www.youtube.com/watch?v=oM0oBuhTLRI[/youtube] http://www.youtube.com/watch?v=oM0oBuhTLRI" As some of you may be aware, the 150th anniversary of Charles Darwin’s Origin of Species is later this month, the 24th to be precise. In one week from today, a special abridged edition of the book...

Actually, looking back over the problem, I think I assumed my 2 X 2 cross product was a cofactor expansion, where it should have been a constant. This would have allowed me to simplify that result and get the 128 \pi^3 I needed in the numerator. Cofactor expansion results in 0 \vec{i} +...

The original question is: Find the curvature of \vec{r}(t) = 4cos(2 \pi t)\vec{i} + 4sin(2 \pi t)\vec{j} I have a solutions guide and found the curvature using K = \frac{||\vec{T}'(t)||}{||\vec{r}'(t)||} but I wanted to try the cross product method to see if it is...

I've been using various methods of finding curvature, and using the formula K=\frac{||\vec{r}'X \vec{r}''||}{||\vec{r}'||^3} I took the cross product of my two vectors and came up with (just assume this is correct, if my question isn't answered i'll post all related work)...

I thought this was interesting, it's from ZapperZ's thread in general discussion. If you notice in the "Today's Top 20 Viral Videos" section just below, http://www.viralvideochart.com/youtube/sarah_palin_cant_name_a_newspaper_she_reads?id=xRkWebP2Q0Y" is posted. She seems to have a hard...

This is a really awesome game. I wish I had the creativity of some of their forum veterans. Many of their members post solutions much like you guys are, check out a couple of solutions I found to level seven, I just made a long cart. =( http://FantasticContraption.com/?designId=600855...

The sound is messed up on that one, sounds much better IMO and a great promotion for the LHC. I found it as a featured article on Yahoo and since I first saw it almost a million others have viewed it.

So, here’s the situation. My roommate and I live on the third floor of our apartment complex. As you walk into the building and begin to climb the stairs to the third floor you would notice a tremendous increase in temperature regardless of the weather. We have air conditioning but its not...

I use This site which allows you to play around with latex, and when it’s output you can copy and paste the image into MSword or whatever you have. Just another option.

I guess I phrased that poorly, I simply meant that the integral was in a specific form which can be dealt with easily when you look at the powers of Sin and Cos. In this case he would want to break up Sin^3(13x) using Sin^2(x) + Cos^2(x) = 1 because the power of the sine function is odd.