Recent content by Sabellic

I don't understand. My teacher said that The period of the graphs on transformed sine and cosine functions can be found by the following formula: 2pi/|b|. As well, whenever I did my previous questions using 360/|b| I got the correct answer.:confused:

Pendulum Ride - Trigonometric Function Homework Statement At Canada's Wonderland, a thrill seeker can ride the Xtreme Skyflyer. This is essentially a large pendulum of which the rider is the bob. The height of the rider is given for various times: Time(s) 0 1 2 3 4 5 6...

This is what I am getting: -2(x- 90)= arcsec(-1.5) -2(x- 90)=0.999657325 x-90=-0.499828662 x=89.5

editted

This is a continuation of my previous post, so please bear with me Homework Statement Find the zeroes of the following function: y= 2 sec (-2x+180deg) + 3Homework Equations Break down the equation into: y= 2 sec -2(x-90deg) + 3; Finding zeroes, means finding the x values when y=0...

You know, that's starting to make sense. I will try this. Thank you, HallsofIvy!

TI-83 problem...Secant Graphs Homework Statement What are the properties of: y= 2 sec(-2x + 90deg) + 3 Homework Equations sec (x) = (1/cos (x)) The Attempt at a Solution I have a problem with finding the Domain of y= 2 sec(-2x + 180deg) + 3. First of all, I have to put the...

Homework Statement If cos x = a/b and tan x = c/d; where a, b, c do not equal 0, then sin x is... (a) bd/ac (b) bc/ad (c) ad/bc (d) ad/bc Homework Equations The Attempt at a Solution The way I see it, if cos x = a/b, then b=hypotenuse. if tan x = c/d, then d=...

Oh, yes. I see. It's about adding it to 180 degrees. Dang that's sneaky. Thanks snipez. I understand what I did wrong. Well not 100%, but almost.

Ok. Don't worry. I'll get the rest. I really, really, really appreciate all your help. I couldn't have done it without you. Thanks snipez.

Ok. I will check extraneous roots: 2sinx - 1 = 3 cosx + 2 2 sin (12/13) - 1 = 3 cos (12/13) + 2 -0.96777993 = 4.999610675 They don't equal. EDIT: Oh, I understand what I did wrong. It is not 67 degrees. 67 degrees is like the reference angle.

I don't follow the last part you are talking about though. Why did you had 0-3?

but, if I use: 13sinx - 12=0 13sinx = 12 sinx = 12/13 This equals 67 degrees. But the points of intersection are: (112.62, 0.8461) and (180, -1)

let's see: (2sinx - 3) (2sinx -3) = 9 (1-sin^2x) 4sin^2 - 6sinx - 6sinx + 9 = 9 - 9sin^2x 4 sin^2x - 12sinx + 9 = 9 - 9 sin^2x 13sin^2x - 12sinx = 0 sinx (13sinx - 12) = 0 Like that?

y= 2sinx - 1 and y= 3cosx + 2 therefore 2 sinx - 1 = 3cosx + 2 2 sinx - 3 cosx = 2 + 1 2sinx - 3cosx = 3 BTW, I thank you very much for trying.