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This is a continuation of my previous post, so please bear with me

Find the zeroes of the following function:

y= 2 sec (-2x+180deg) + 3

Break down the equation into:

y= 2 sec -2(x-90deg) + 3;

Finding zeroes, means finding the x values when y=0, therefore:

0=2 sec [-2(x-90deg)]+3

0=2 sec [-2(x-90deg)]+3

-3 = 2 sec [-2(x-90deg)]

-1.5 = sec [-2(x-90deg)]

-1.5/sec = [-2(x-90deg)]

^ this is where I get stuck. Because the inverse of sec or cos (sec^-1; cos^-1) is Error or Undefined. So the whole thing explodes. Now, I can tell when the graph crosses the x-axis (and therefore has a y=0 value) on a Graphing tool, but how can I find this out algebraically?

Thanks for the assistance.

## Homework Statement

Find the zeroes of the following function:

y= 2 sec (-2x+180deg) + 3

## Homework Equations

Break down the equation into:

y= 2 sec -2(x-90deg) + 3;

Finding zeroes, means finding the x values when y=0, therefore:

0=2 sec [-2(x-90deg)]+3

## The Attempt at a Solution

0=2 sec [-2(x-90deg)]+3

-3 = 2 sec [-2(x-90deg)]

-1.5 = sec [-2(x-90deg)]

-1.5/sec = [-2(x-90deg)]

^ this is where I get stuck. Because the inverse of sec or cos (sec^-1; cos^-1) is Error or Undefined. So the whole thing explodes. Now, I can tell when the graph crosses the x-axis (and therefore has a y=0 value) on a Graphing tool, but how can I find this out algebraically?

Thanks for the assistance.

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