If cos x = a/b and tan x = c/d; where a, b, c do not equal 0, then sin x is.....
The Attempt at a Solution
The way I see it, if cos x = a/b, then b=hypotenuse.
if tan x = c/d, then d= hypotenuse (two hypotenuse values?) and c = opposite.
Therefore sin x = c/d. I don't know why the answers in the book use products of the vairables in their numerators and denominators.
Much thanks in advance.