\begin{equation}
m_2.g-T_2=m_2.a
\end{equation}
\begin{equation}
T_1-m_1g=m_1.a
\end{equation}
If i use torque
\begin{equation}
T_2.R-T_1.R=M.R^2.\alpha\div{2}
\end{equation}
\begin{equation}
\alpha.R=a
\end{equation}
If there is misunderstanding in your mind, you will ask me.
You are wrong in 2TR because the tension direction opposite and also the rope's tension isn't same in this equation. I will add true equations in few minutes
In my equations A is area. In my equation
\begin{equation}
A=4.\pi.r^2=S
\end{equation}
I should have S for this for doesn't mixing the question provided and asked constant.
And also i had mistake in the above post
\begin{equation}
N=n.V
\end{equation}
where is V volume, n tota number of star...
You are wrong in final equation.
\begin{equation}
N=n.A.l
\end{equation}
You know
\begin{equation}
n = \int_{L_{min}}^{L_{max}} n(L)dL.
\end{equation}
If we put this to first equation we get
\begin{equation}
N = \int_{L_{min}}^{L_{max}} n(L)A.LdL.
\end{equation}
Other equations are true, i think
sorry, i will continue:
$\sigma_2$ positive, $\sigma_1$ is negative; so current of outer sphere is anticlockwise, current of inner sphere is clockwise.
\begin{equation}
i_1=q_1\div{T}=\sigma_1.2.\pi.r_1h\div{2\pi/\omega}=\sigma_1.\omega.r_1.h
\end{equation}
\begin{equation}...
Homework Statement
Two coencenteric metalic shell has inner radius $r_1$ outer radius $r_2$. We place along axis infinity wire has $\lambda$ charge in per unit length. The inner region of metalic shells inserted with relative permabilitty coefficent $\epsilon$. This system rotates with $\omega$...