Recent content by sArGe99

Yes. That's correct.

Yes it is. It should be 2*n*m*v?

The force on the pan will be 2*n*d/dt(m*v) n being the number of beads hitting the pan per unit time. v being the VERTICAL velocity of a bead as it hits the pan.

We're only concerned with what happens after the inelastic collision. Conservation of energy is valid then.

What was your "v" in 1/2 mv^2?? You need to apply Conservation of Linear Momentum principle in the horizontal direction (as there are no external forces in this direction) to obtain the velocity of the combined mass after collision. Then obtain the maximum compression "x" at which the combined...

Figure??

Was just telling you there would be 6 pairs to consider.

I don't really understand how this can be a one-dimensional problem. If it is, you first have to find the acceleration using what is given. ie. Final velocity = 0 Initial velocity = 3.3 m/s Displacement = 0.11 m Try v2 - u2 = 2*a*s to find out the acceleration and multiply it with the mass...

You will have 4C2 combinations to consider. Two of these will be diagonally opposite pairs and all others will be adjacent pairs.

Since the first pulley(the smaller one) is physically connected to the first block, you have to treat the pulley as being a part of the block. So the force experienced by the (block+small pulley) is 2T while the tension force in the other block is only T. Remember that tension in the string is...

When kept in contact, the potentials of the spheres equalize. Since the spheres are of same radius, this would mean that the charges on the spheres equalize. As you correctly said, the final charge on each sphere will be Q1 + Q2 /2 Charge transferred = Q1 + Q2 /2 - Q2 (Final - Initial) Q1 -...

Yes, the magnetic force provides the necessary centripetal force for the circular motion of the electrons. Fm = q (v X B) = m*v2 / r Don't really know much about b-bar. The units should be either Tesla or Gauss.

Oh.. Circular loop as an equivalent bar magnet. I thought vector l = vector l(final) - vector l(initial) Final and initial points are the same for a circular loop, so l=0

I know that two infinitely long straight conductors will attract each other when kept parallel if current flows in the same direction in both. If two circular loops are placed such that their planes are parallel, current in the same direction, will they attract? Also, does a loop carrying...

Let x denote the extension of the wire downwards and L the natural length of the rope. If theta is the angle b/w x and length of wire in deformed state, you should get cos theta = x/(L/2) after a bit of approximation.ie. taking (L/2) outside the root from denominator. 2T cos(theta) = mg...