What Is the Minimum Strength of a Fishing Line to Stop a Drifting Salmon?

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Homework Help Overview

The discussion revolves around determining the minimum strength required for a fishing line to stop a drifting salmon weighing 87 N over a distance of 11 cm, with the fish initially moving at a speed of 3.3 m/s. The problem involves concepts of force, mass, and acceleration under the assumption of constant deceleration.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between force, mass, and acceleration, with some attempting to apply kinematic equations to find acceleration. Questions arise regarding the correctness of mass calculations and the interpretation of the problem as one-dimensional.

Discussion Status

The discussion is ongoing, with participants sharing their attempts and questioning their calculations. Some have provided alternative approaches to finding acceleration, while others express uncertainty about their previous results.

Contextual Notes

There is a mention of potential confusion regarding the dimensionality of the problem and the need to relate various equations. Participants are also grappling with the implications of their assumptions and the accuracy of their calculations.

MFlood7356
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1. The tension at which a fishing line snaps is commonly called the line's “strength.” What minimum strength is needed for a line that is to stop a salmon of weight 87 N in 11 cm if the fish is initially drifting horizontally at 3.3 m/s? Assume a constant deceleration.

2. F=ma, W=mg

3. I have a feeling this problem is really easy I just don't know how to do it. I thought I did it correct below but my answer is wrong. Can someone help me please?

W=87N d=0.11m a+3.3m/s
m=87/9.8= 8.89kg
F=(3.3m/s)(8.89kg)= 29.3N
 
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I don't really understand how this can be a one-dimensional problem.
If it is, you first have to find the acceleration using what is given. ie.
Final velocity = 0
Initial velocity = 3.3 m/s
Displacement = 0.11 m
Try v2 - u2 = 2*a*s to find out the acceleration and multiply it with the mass of the body under consideration.
 
Oh okay. I had no idea I had to relate those equations. Is my mass that I have above correct?
 
So I just tried it and still got it wrong. Here's what I did.

a= 3.32/0.22= 49.5
 

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