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Homework Statement We have a town we three papers. Paper 1 is read by 64 % of pop. Paper 2 is read by 46 % of pop. Paper 3 is read by 54% of pop. 3% read both Paper 1 and Paper 2. 8% read both Paper 1 and Paper 3. 12 % read Paper 2 and Paper 3. 5% read all three...

yeah there is only one unique solution.

I got it now :D

thank and then I should be able to arrive at the solution ? But if I solve the rewritten equation with respect to z I get z=-b^2*t^2/(t^2-p^2)? I am no closer to y = b/(sqrt(p/t +1) * sqrt(p/t-1)) which is suppose to be the solution for original equation. Which is still no closer to y =...

Thats easy a/b - c/d = ad/bd - bc/bd = (ad-bc)/bd But regarding the other expression I attempted now 10 times if I take my equation X(y) = y/(t*(sqrt(b^2+y^2)) - 1/p = 0 and use the commen denominator (p*t(b^2+y^2)) I end up with the expression: py/(pt*sqrt(b^2+y^2)) -...

Okay, Glad I am not totally stupid then :) So any if I take the original equation : y/(t*(sqrt(b^2+y^2)) - 1/p and use the commen denominator p*t*sqrt(b^2+y^2) I arrive at py/(p*t*sqrt(b^2+y^2) - (t*sqrt(b^2+y^2)/(p*t*sqrt(b^2+y^2) = y/(t*sqrt(b^2+y^2)) - 1 = 0 ? But if...

I get that now but the only commen denominator I can deduce is my pee size brain is :) p*t*(b^2+y^2)) But what I get from what you are saying is that denominator is wrong?

So I am lost here :( What would you surgest I do as a first step with original equation? I can add 1/p on both sides I see that and next add the denominator on both sides. But what next?

You are right. I see now the equation I am suppose to solve is y/(t*(sqrt(y^2+b^2))-1 = 0 Is it correct now?

Thank you for your answer. That implies that I need to solve the equation (y*p - t*p*(sqrt(y^2+b^2)) = 0 Which allows me to arrive at the solution (using my graphical calculator) y = -b * p *(sqrt(-1/(p^2-1) But solution is suppose to be: y = b/(sqrt(p/t +1) * sqrt(p/t-1))...

Homework Statement Given the following equation X(y) = y/(t*(sqrt(b^2+y^2)) - 1/p How would I go solving that equation X(y) = 0 with respect to y? The Attempt at a Solution I can choose a commen dominator called p*t*(b^2+y^2) But I when end up with ((y*p -...

try posting your drawing of the situation.

I am not sure here is it then just F_G * sin (theta) and do I need to multiply this with the distance betweem the chair's leg and the wall?

Which first term are you referring to?

F_G?