Two charges -Qo and -3Qo, are a distance l apart. These two charges are free to move but do not because there is a third charge nearby. What must be the charge and placement of the third charge for the first two to be in equilibrium.
This would be easier if I was given an l amount, but...
So with the side triangle: I found the height to be 13.51cm
With the bottom dashed triangle... because I need the height to reach the centre, I divided the height of that dashed triangle by 2, so I got: 6.7cm
Using the side triangle height, the half height of the bottom dashed triangle and...
I'm sorry, I'm really horrible visualizing this, but I think I get what you mean!
So, I found the height of the bottom dashed triangle.
I divided it in half...
Used it with the height of the side triangle I originally found
And with Pythagorean Theorom, found the height at the centre then...
mhmm, so here is what I did... With the 15.6cm, I used Pythagorean to find the height to be 13.5cm of the side triangle. Then Pythagorean theorom again to find the height of the center, which I calculated to be 11.0cm. Divided that by 2 to get the centre of the triangle.
Am I in the right...
Thanks for the replies!
Please correct me if I'm wrong
So first, I used the formula Q=CV to look for the charge of the capacitor connected to the 55V battery. Since the battery is removed, the charge Q remains the same right? Now when the dielectric material is inserted to fill the space...
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A simple type of blinking light circuit can be constructed using a neon lamp. The circuit shown here has a 4.0 μF capacitor in parallel with a neon lamp. When the voltage is low in the RC portion of the circuit, the lamp does not conduct electricity. Therefore, it is effectively not there from...
Consider an equilateral triangle of side 15.6cm. A charge of +2.0μC is placed at one vertex and charges -4μC each are placed at the two. Determine the electric field at the centre of the triangle.
I used Pythagoreom theory to find the height and divided it by 2 but now I'm stuck because I...
Two 1.0g beads are charged equally and placed 50cm apart. When released, they begin to accelerate at 150m/s2. What is the magnitude of the charge on each bead?
The equations I used:
F = ma
F = kQQ / r2
I was just wondering about the mass. Do I have to use the total mass (2.0g) for both...