Recent content by Sick0Fant

Thanks a bunch!

I've got a follow-up question: I have to prove that the maximum value of |P_2(x)| with x in [x_0,x_2] is (2*(3)^(1/2)/9)*h^3. Any ideas?

What I have is this: Let P_n(x)=(x-x_0)(x-x_1)...(x-x_n), _i are subscripts. Prove that the maximum value of |P_1(x)| for x in [x_0,x_1] is h^2/4, where h =x_1 - x_0. All the x_i terms are evenly spaced. That is, x_(i+1)-x_i is the same for all i. What I noticed is that P_1(x_0)=P_1(x_1)=0...

I already had thought of that: you have y - e< z < y. Take e to be 1/k with e going to infinity, then {z_k} cgt to y, but what can we really conclude from that? Is there any guarantee that a {z_k} is in the original seq?

Okay. The problem I have is: Let {x_n} be bdd and let E be the set of subsequential limits of {x_n}. Prove that E is bdd and E contains both its lowest upper bound and its greatest lower bound. So far, I have: {x_n} is bdd => no subseq of {x_n} can converge outside of {x_n}'s bounds=>E...

Must be in my class!

I rarely care enough about one problem to ask for help, but there are a million problems that are similar to this one and I don't really understand any of them. The problem I'm looking at reads: In a room there are 10 people, none of whom are older than 60 (ages are considered as whole...

You can use whichever one you want. You can integrate using any shape. If you're doing the solids of revolution problems, I always thought that the shell method was easier.

The general idea is to multiply the numerator and denominator by the inverse of x raised to the largest power of the denominator. Then, evaluate the limit.

Is the answer approximately .046641?

I think this is it. log(base 5)x=ln(x)/ln(5) d/dx(ln(x)/ln(5)=1/(ln(5)x) If not, then I'll hit myself over the head with my Calc book. EDIT: I guess somebody pretty much said the same thing before I did... sorry.

Q: Surface Area A solid os formed by adjoining two hemispheres to the ends of a right circular cylinder. The total volume of the solid is 12 cubic centimeters. Find the radiusof the cylinder that produces the minimum surface area. A: SA=2 π r2 + 2 π r h V=πr^2h, V=12 h=12/(πr^2)...

Well, I can try to help you, but I don't have enough time to work it out. You want to find the rate of change of the area, so you'll need to use a=1/2bh Then eventually differentiate. You should use properties of similar triangles to solve for the unknown. then...