Recent content by skybox

Thanks for the help. This is becoming a very complicated solution :S Will just use Matlab to solve!

Woops. Updated. All expressions equal 0

Homework Statement Solve the following equation for P_{1} and P_{2} Homework Equations 7.0+0.004P_{1}-\lambda(1-0.0004P_{1})=0 7.0+0.004P_{2}-\lambda=0 P_{1}+P_{2}-500-0.0002P_{1}^{2}=0The Attempt at a Solution I am having some issues on ways to solve this problem. I guess the main point I am...

Thanks all for the replies. I think I have an idea on how to solve the problem with all the hints given. I will not post the solution once I do come to a solution. Thanks again!

Homework Statement Homework Equations The area of a circle: A_c = \pi r^{2} The Attempt at a Solution I know that the diameter of the oval shape is 10m since the problem says that it touches the circumference of the center of each circle. I am not sure how to approach the problem...

I was able to solve it! Attached is the solution (as an image I did in Word) if anyone is interested.

Thanks tiny-tim. After some research, looks like this is a parametric equation. Since it has cosines and sines, it will most likely be a circle or ellipse from 0<=x<=2\pi. I will try to solve this and post the solution when done. Thanks again!

Homework Statement The x and y coordinates of a particle moving in the x-y plane are x=8sin(t) and y=6cos(t). What is the equation of the path of the particle? Homework Equations m=\frac{y_2-y_1}{x_2-x_1} y-y_1=m(x-x_1) The Attempt at a Solution I am stuck on how to approach this...

Thanks guys! I finally solved it and got a better understanding of the problem. Attached is the solution I created in word when trying to solve this problem. Thanks again for everyone's help.

Thanks pongo. I drew it out and understand why my thinking was incorrect on trying to subtract the whole circle. So I drew it out: Now I am confused on how to continue to approach this problem. I am not sure if the the portion of (B) is exactly a half circle, which I cannot assume given...

Thanks for the reply pongo38. I might be confusing myself. If I take area of the whole circle and subtract it with the area of the triangle, won't that give me the area of the smaller circle?

Thanks. I researched this and it looks like I can use the SAS (Side Angle Side) formula to get the area of this triangle. That formula is: A=\frac{1}{2}ab\sin C Which, for my problem, is equal to: A_t = \frac{1}{2}(7)(7)\sin 150\degree A_t = \frac{1}{2}(49)(0.5) A_t = \frac{49}{4} Now...

Hmmm, yes you are right. Looks like I made a mistake. Can I assume it is a right triangle if I cut it in half?

Hi all, I am having an issue trying to solve the following problem Homework Statement I know that the radius of the circle is 7 and the angle of the segment is 150° Homework Equations Area of a circle: A = \pi{r}^2 Area of the sector of the circle: A = \frac{n}{360}\pi r^{2} Area...

Great. I think I got it. Since this equation is in the form of: x=y^{2} it is a parabola with the general equation of x = a(y-k)^{2} + h. a = 1 and k = 0 in this case. The focus point for a parabola in this form is at (h+p, k) And p = \frac{1}{4a}. Therefore, since a = 1, p=\frac{1}{4}...