Recent content by SMOF

And, if you ask me, this is one of the great thibgs about science. Scientists are willing (generally) to revise what they know ...to say "Ok, I know a bit more information now, so that means what I thought was right before has changed a bit". I wonder would your philosophy teacher be so open...

Hello. I was womdering does anyone know any good resources of information on Fermi level de-pinning & Schottky barriers? I have been hunting around online, with not much luck. I thought someone here might be able to suggest some things. Thanks. Seán

Yes, two. One, I am a bit of an idiot, and two, I should have been asleep hours ago! Sorry about that :redface: Yes, I think I have it now. Thanks for everyones help! And I shall make sure I read over what I have written before I submit it in future! Again, many thanks. Seán

Hello, thanks for the reply! Right, am I right in saying that the de^(x-d)-(x-d) comes to e^0 = 1? But the why is the other other exponential all over d, and not d - d? Thanks. Seán

Hello. Sorry, there was a typo, the second line should have been \frac{d}{D_pB}\int e^{x/d}(-de^{-W_B/d} + de^{-x/d}) dx Working out the brackets, I get e^{x/d}(-de^{-W_B/d} + de^{-x/d}) dx goes to (I think) -de^{x-W_B/d} + de^{d} I am not sure about the de^d part. Seán

Hello. I am going through some worked examples for a class I have, and there is one step I don't understand, and I hope someone can help me with that. It goes from \frac{1}{D_pB}\int e^{x/d}(-de^{-W_B/d} + de^{-x/d}) dx to \frac{1}{D_pB}\int (1 - e^{x-W_B/d}) dx The limits are...

Hello. This is cool, thanks for all the replies. It is cool to see how things can be dealt with from different positions. Seán

Couldn't have said it better! It is a lesson I am learning myself. Seán

Hello, Rather than start another topic, since this question is related to this tread, I thought I would just tack it on here. We were asked to "Derive a formula for the output signal y as a function of t". I think I have done this correctly, but would be very grateful if someone could cast...

Grand, I'm with you now. Seán

Well, the online reference I used to make sure said d/dt sin x = cos x. So, I was taking x = wt. Anyway, that is neither here nor there. Again, thank you for all your help, and I will check out that book you mentioned. Seán

Hello, Well, differentiating a constant is zero, but I am not sure of that holds for 0. And differentiating sin(wt) would be cos(wt). I have done a course in electrical circuits, but it is all very rusty, and very much from a hands on point of view. Seán

So, if I have it right, it should be y'(t) + 2y(t) = x(t)? Yea, that would be great! I really want to learn as much as I can! And again, thanks so much for all your help. Hopefully (if I finally have it right) I will be able to do it myself. Seán

The sY(s) is the is the first derivative y'(t) No worries, it is nearly 3am here, and I need some sleep! Thanks. Seán

That should be sY(s) + 2Y(s) = X(s)